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In-s [12.5K]
3 years ago
10

Need to know if these are correct, and if not what are the correct ones?

Mathematics
1 answer:
Tems11 [23]3 years ago
4 0
(3) The correct answer for the question that is being presented above is this one: "Third choice."
item 1 = 1 + 4 + 9 = 14
item 2 = 1 + 8 = 9
item 3 = 2 + 3 + 4 + 5 = 14
item 4 = 6 + 8 = 14

(4) The correct answer for the question that is being presented above is this one: "Second choice."
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Three equal ratios to 6/7
Rashid [163]
12/14 , 18/21 , 24/28
4 0
3 years ago
Read 2 more answers
Value of 3 to the power of -2
Kisachek [45]

Answer:

it would be .1111111111

Hope this helps

6 0
2 years ago
Read 2 more answers
pam deposited $6,900 in a savings account with simple interest. Four months later she had earned $23 in interest. What was the i
3241004551 [841]

Answer:

1%

Step-by-step explanation:

We use the simple interest equation of A=P(1+rt).

A-the total amount with interest earned

P-the initial amount or principal

r-rate

t-time in years

We substitute the values P=6900, A=6923, and t=0.33 since 4 months divided by 12 months is 0.333 years. We then solve for r.

6923=6900(1+r(0.33))\\6923=6900(1+0.33r)\\\frac{6923}{6900} =\frac{6900(1+0.33r)}{6900} \\1.0033=1+0.33r\\1.0033-1=1-1+0.33r\\0.0033=0.33r

Our final step is to divide both sides by 0.33.

\frac{0.0033}{0.33} =\frac{0.33r}{0.33} \\0.01=r

This is the decimal of the rate. We convert to a percentage by multiplying by 100. 0.01(100)=1%.


5 0
3 years ago
The table shows the data of a random sample of fish that were collected from and later released into a lake.
yan [13]
280 eels

92 + 56 + 52 = 200
eel = 56/200

 56    *5       x   
-----    =   --------
200   *5   1000
56(5) = 280 x = 280

56/200 = 7/25 
7/25 = 280/1000
6 0
3 years ago
True or false: A) Any two different points must be collinear. B) Four points can be collinear. C) Three or more points must be c
Tasya [4]

Answer:

A) True

B) True

C) False

Step-by-step explanation:

Knowing that the collinear points are all those that pass through a line, we have:

A) given two points they form a line, by themselves they are collinear  (graph 1)

B) Can be or not can be (graph 2)

C) Can be not must be (graph 3)

8 0
3 years ago
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