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topjm [15]
3 years ago
15

Please answer Question #6

Mathematics
1 answer:
irina [24]3 years ago
7 0
You would have to do 3/4 times 4/5 to get the area. 3/4•4/5= 12/20 if you simplfy you would get A. 3/5
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Through: (-5, -3), perp. to y=-9/4x-5
Mrrafil [7]

Given:

A line passes through (-5,-3) and perpendicular to y=-\dfrac{9}{4}x-5.

To find:

The equation of the line.

Solution:

We have,

y=-\dfrac{9}{4}x-5

On comparing this equation with slope intercept form, i.e., y=mx+b, we get

m_2=-\dfrac{9}{4}

It means, slope of this line is -\dfrac{9}{4}.

Product of slopes of two perpendicular lines is always -1.

m_1\times m_2=-1

m_1 \times \left(-\dfrac{9}{4}\right)=-1

m_1=\dfrac{4}{9}

Slope of required line is \dfrac{4}{9} and it passes through the point (-5,-3). So, the equation of the line is

y-y_1=m(x-x_1)

where, m is slope.

y-(-3)=\dfrac{4}{9}(x-(-5))

y+3=\dfrac{4}{9}(x+5)

9(y+3)=4(x+5)

9y+27=4x+20

27-20=4x-9y

7=4x-9y

Therefore, the equation of required line is 4x-9y=7.

8 0
3 years ago
HELPPPPPPP!!!!!!!!!!!!!
Sonbull [250]
14.23 is your answer!!!!!!!
4 0
3 years ago
Read 2 more answers
What values of x satisfy the equation 2x^2 -3x +4 =0
BaLLatris [955]

Answer:

(3 ± √23 * i) /4

Step-by-step explanation:

To solve this, we can apply the Quadratic Equation.

In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)

Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4

Plugging these values into our equation, we get

x = (-b ± √(b²-4ac))/(2a)

x = (-(-3) ± √(3²-4(2)(4)))/(2(2))

= (3 ± √(9-32))/4

= (3 ± √(-23))/4

= (3 ± √23 * i) /4

6 0
3 years ago
The triangle below are drawn on 1-cm dot paper. find the perimeter of each triangle
AnnyKZ [126]
There is no triangle below. Try to edit this problem.
4 0
3 years ago
Find the distance between the points (–3, 2) and (0, 3).
Oksi-84 [34.3K]

Answer: \sqrt{10}\ units

Step-by-step explanation:

You need to use the following formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given the points  (-3, 2) and (0, 3), you can identify that:

x_2=-3\\x_1=0\\\\y_2=2\\y_1=3

Then, the final step is to substitutes these coordinates into the formula.

So, the distance between the given points is:

d=\sqrt{(-3-0)^2+(2-3)^2}\\\\d=\sqrt{10}\ units

6 0
3 years ago
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