Given:
A line passes through (-5,-3) and perpendicular to 
.
To find:
The equation of the line.
Solution:
We have,
On comparing this equation with slope intercept form, i.e., 
, we get
It means, slope of this line is 
.
Product of slopes of two perpendicular lines is always -1.
Slope of required line is 
and it passes through the point (-5,-3). So, the equation of the line is
where, m is slope.
Therefore, the equation of required line is 
.
14.23 is your answer!!!!!!!
Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
There is no triangle below. Try to edit this problem.
Answer: 
Step-by-step explanation:
You need to use the following formula:
Given the points (-3, 2) and (0, 3), you can identify that:
Then, the final step is to substitutes these coordinates into the formula.
So, the distance between the given points is:
