True... is there any specific to your question?
Answer:
(a) 91 employees were absent fewer than six days.
(b) 22 employees were absent more than five days.
(c) 20 employees were absent from 6 up to 12 days.
Step-by-step explanation:
The data for the number of days absent during a calendar year by employees of a manufacturing company is given below.
(a)
The number of employees that were absent for fewer than six days is =
![Frequency\ for\ class\ [0\ - \ 3]+Frequency\ for\ class\ [3\ - \ 6]\\=60 +31\\=91](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B0%5C%20-%20%5C%203%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B3%5C%20-%20%5C%206%5D%5C%5C%3D60%20%2B31%5C%5C%3D91)
Thus, there were 91 employees who were absent for fewer than six days.
(b)
The number of employees that were absent for more than 5 days is =
![Frequency\ for\ class\ [6\ -\ 9]+Frequency\ for\ class\ [9\ -\12]+\\Frequency\ for\ class\ [12\ - \15]\\=14+6+2\\=22](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B6%5C%20-%5C%209%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B9%5C%20-%5C12%5D%2B%5C%5CFrequency%5C%20for%5C%20%20class%5C%20%5B12%5C%20-%20%5C15%5D%5C%5C%3D14%2B6%2B2%5C%5C%3D22)
Thus, there were 22 employees who were absent for more than 5 days.
(c)
The number of employees that were absent from 6 up to 12 days is =
![Frequency\ for\ class\ [6\ -\ 9]+Frequency\ for\ class\ [9\ -\12]=14+6\\=20](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B6%5C%20-%5C%209%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B9%5C%20-%5C12%5D%3D14%2B6%5C%5C%3D20)
Thus, there were 20 employees who were absent from 6 up to 12 days.
Answer:
- jet in still air: 712 mi/h
- jetstream rate: 50 mi/h
Step-by-step explanation:
The relation between speed, time, and distance is ...
speed = distance/time
Against the wind, the speed is ...
(3310 mi)/(5 h) = 662 mi/h
With the wind, the speed is ...
(3810 mi)/(5 h) = 762 mi/h
The jet stream adds to the speed in one direction, and subtracts in the other direction, so the difference in travel speeds is twice the speed of the jet stream:
(762 mi/h -662 mi/h)/2 = jet stream speed = 50 mi/h
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The speed of the plane is the average of the two speeds, or the sum of jet stream speed and the lower speed, or the difference of the higher speed and the jet stream speed. Any of these calculations will give the plane's speed in still air:
(762+662)/2 = 662 +50 = 762 -50 = 712 . . . mi/h
What you want to do is take 9 and multiply 9 by itself 5 times as shown (9*9*9*9*9) and you get 59049 then you take that number and divide it by 2 so 59049/2 is 29524.5