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Svetllana [295]
3 years ago
11

Charles has 2 2/3 ounces of seeds. He needs 4 4/5 ounces in order to complete the garden. How much more seeds he need?

Mathematics
1 answer:
yawa3891 [41]3 years ago
5 0

Answer:

Charles need 3\frac{1}{5} more ounces of seeds.

Step-by-step explanation:

Given that:

Quantity of seeds Charles has = 2\frac{2}{3} = \frac{8}{3} ounces

Quantity of seeds Charles need = 4\frac{4}{5} = \frac{24}{5} ounces

Let,

x be the number of remaining seeds Charles need.

x = Seeds needed - Seeds Charles already have

x = \frac{24}{5}-\frac{8}{3}

x = \frac{72-24}{15}

x = \frac{48}{15}

x = \frac{16}{5}

x = 3\frac{1}{5} ounces

Hence,

Charles need 3\frac{1}{5} more ounces of seeds.

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Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

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x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

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4x^{2} +20x-39=0

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a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

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x=\frac{-20(-)32} {8}=-6.5\ in

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(4+2x)=4+2(1.5)=7\ in

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