Question

A straight-line graph

Answer 1

Given:

A straight-line graph  has gradient 4  and crosses the y axis at (0, −3).

To find:

The equation of the given graph.

Solution:

The slope intercept form of a line is:

$y=mx+b$            ...(i)

Where, m is the slope of the line and b is the y-intercept.

A straight-line graph  has gradient 4. It means the slope of the line is 4.

$m=4$

Line crosses the y axis at (0, −3). So, y-intercept is -3.

$b=-3$

Putting m=4 and b=-3 in (i), we get

$y=(4)x+(-3)$

$y=4x-3$

Therefore, the equation of the given line graph is $y=4x-3$.