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nlexa [21]
3 years ago
10

A straight-line graph

Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Given:

A straight-line graph  has gradient 4  and crosses the y axis at (0, −3).

To find:

The equation of the given graph.

Solution:

The slope intercept form of a line is:

y=mx+b            ...(i)

Where, m is the slope of the line and b is the y-intercept.

A straight-line graph  has gradient 4. It means the slope of the line is 4.

m=4

Line crosses the y axis at (0, −3). So, y-intercept is -3.

b=-3

Putting m=4 and b=-3 in (i), we get

y=(4)x+(-3)

y=4x-3

Therefore, the equation of the given line graph is y=4x-3.

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