distance = speed * time
the first bus speed = x
second bus = x - 12
the sum of distance = 765 miles
first distance = 6x
second distance = 6 (x -12)
6x + 6(x-12) = 765
x + x -12 = 127.5
2x = 139.5
x = 69.75 mi/h which is the faster bus
the second bus speed = 57.75 mi/h
Answer:
The inequality describing the situation is:

Step-by-step explanation:
Joe works as a busboy at the rate of = $7 per hour
Let the number of hours he works as a bus boy this month be =
hours
∴ Amount Joe would make this month working as a busboy =
Joe works as a theater usher at the rate of = $9 per hour
Let the number of hours he works as a theater usher this month be =
hours
∴ Amount Joe would make this month working as a theater usher =
Total amount Joe would make this month =
His goal is earn more than $1500 this month.
∴ The situation can be represented in the following inequality:

10*30=300
10*4=40
6*30=180
6*4=24
add them up: 300+40+180+24=544
The answer to your question is Y=12
The correct answer is C) 71