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Tema [17]
3 years ago
14

A fair dice is rolled 3 times in a row. The outcomes are shown below. Calculate the probability of all three events occurring. R

oll Outcome 1st 5 2nd factor of 6 3rd more than 1
Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

5/54

Step-by-step explanation:

probability of the dice being 5 = 1/6

probability of the dice being a factor of 6 = 4/6

probability of the dice being more than 1 = 5/6

1/6 * 4/6 = 4/36

4/36 * 5/6 = 20/216

20/216 simplified to lowest is equal to 5/54

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7. A crate of soft drinks contains 9 bottles of coke, 6 bottles of pepsi and 4 bottles of limca. Ademola picks one bottle of sof
Mekhanik [1.2K]

The probability that the events (a) they both picked Limca = 0.04, (b) Ademola only picked Pepsi = 0.32, (c) They both picked the same brand = 0.33 (d) They picked different brand=0.67.

<h3>What is probability?</h3>

Probability is the fraction of the required outcome event divided by the number of possible outcomes of events.

Total possible outcome of the event of picking drinks contained in the crate = 19

Hence, we can compute the following as follows;

(a) The probability they both picked Limca = (4/19)×(3/18)

Limca = 12/342

Limca = 0.04

(b) The probability Ademola only picked pepsi = 6/19

pepsi = 0.32

(c) The probability they both picked the same brand = (9/19)×(8/18)+(6/19)×(5/18)+(4/19)×(3/18)

=(72+29+12)/342

= 114/342

= 0.33

(d) The probability they picked different brand = (9/19)×(6/18)+(9/19)×(4/18)+(6/19)×(9/18)+(6/19)×(4/18)+(4/19)×(9/18)+(4/19)×(6/18)

The probability they picked different brand = (54+36+54+24+36+24)/342

The probability they picked different brand = 228/332

The probability they picked different brand = 0.67

Therefore, the probability for events (a) is 0.04, (b) is 0.32, (c) is 0.33 and (d) is 0.67.

Know more about probability here: brainly.com/question/24830485

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6 0
1 year ago
Solve the systems by the addition method x - 2y = - 4 2x + y = 7
vfiekz [6]
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To solve this system of equations by addition, our first goal is to cancel

out one of the variables by adding the two equations together.

However, if we add these two equations together right away, nothing

will cancel so we need to set things up so a variable will cancel.

Notice that we have an 2x in our second equation.

If we had a -2x in our first equation, then the x's would cancel out.

In order to create a -2x in the first equation, we simply

multiply both sides of the first equation by -2.

So we have (-2)(x - 2y) = (-4)(-2) which can be rewritten as -2x + 4y = 8.

Now rewrite both equations, as shown below.

<h2>-2x + 4y = 8</h2><h2>2x + y = 7</h2><h2 />

Now when we add the equations together, the x terms

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Dividing both sides by 5, <em>y = 3</em>.

To solve for x, plug a 3 in for y in either one of our 2 original equations.

So let's go with our second equation.

Plugging a 3 in for y, we get 2x + (3) = 7.

Now subtract 4 from both sides to get 2x = 4.

Dividing both sides by 2, we fid that <em>x = 2</em>.

Since x = 2 and y = 3, our answer is the ordered pair (2, 3).

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I really don’t know sorry bro
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