Answer:
It should be the last one because rigid transformations doesn't change in size just where it is
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Answer:
2x + 6
Step-by-step explanation:
= 2(x + 3)
= 2(x) + 2(3)
= 2x + 6
hope this helps
Step-by-step explanation:
They are considered homologous structures because they have a similar underlying anatomy.
Answer:
12+8x
Step-by-step explanation:
By adding together alike values, 5 and 7, and 2x and 4x, you get 12+8x.
