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anastassius [24]
2 years ago
11

Don't guess!! pls help!! THERE'S 4 IMAGES.

Mathematics
1 answer:
creativ13 [48]2 years ago
3 0

Answer:

pic one is rock cycle, pic 2 crystaline structure, and pic three and 4 are the same pictures as question 2

Step-by-step explanation:

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Solve for x. Round to the nearest tenth. Please help
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Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le
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Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes  =68

Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}

68= \frac{\text{Sum of all lengths}}{7}

68 \times 7 =\text{a+b+c+d+e+f+g}

476=\text{a+b+c+d+e+f+g} --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

476=x+x+x+84+84+84+4x+14

476=7x+266

\frac{476-266}{7}=x

30=x

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

7 0
3 years ago
Given the diagram of parallelogram LMNO, solve for s.
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3t - 15 = 3(25) - 15 = 75 - 15 = 60...< m = 60

< m and < o are consecutive angles and they are supplementary....so they add up to 180
< m + < o = 180
60 + < o = 180
< o = 180 - 60
< o = 120

3s = 120
s = 120/3
s = 40

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3 years ago
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