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Svet_ta [14]
2 years ago
12

(WILL MARK BRAINLIEST) Keisha is playing a game using a wheel divided into 8 equal sectors, as shown in the diagram below. Each

time the spinner lands on blue, she will win a prize.
If Keisha spins this wheel twice, what is the probability that she will win a prize on both spins?

Mathematics
1 answer:
yulyashka [42]2 years ago
5 0

Answer:

6/11

Each time you spin the pointer there is a 3/8 for each of the two spins. That means there is a 6/11 chance of the pointer landing on blue for both times the pointer is spun.


Step-by-step explanation:

Each spin there are 8 possible sections the spinner can land on. The circle has 3 blue sections. The question asks what is the probability of the spinner landing on blue for BOTH spins. This means that you would have to show the denominator as 16. Each time you spin the pointer there is a 3/8 chance it will touch blue. When you spin it two times there is a 6/16 probability that the spinner will land on blue for each of the times the pointer is spun.



Have a great rest of your day
#TheWizzer

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Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r
NeTakaya

\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Explanation:</h2>

In this exercise, we have the following functions:

r(x)=2x-1 \\ \\ s(x)=5x

And they are defined for all real numbers x. So we have to write the following expressions:

First expression:

(r-s)(x)

That is, we subtract s(x) from r(x):

(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}

Second expression:

(r\cdot s)(x)

That is, we get the product of s(x) and r(x):

(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}

Third expression:

Here we need to evaluate:

(r+s)(-2)

First of all, we find the sum of functions r(x) and s(x):

(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1

Finally, substituting x = -2:

(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

5 0
3 years ago
Cker
Alenkinab [10]
Option a) is the right answer
7 0
3 years ago
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