1.

Mathematics

2 answers:

Alinara [238K]2 years ago

5 0

Answer: (b) -7/2, 6.

Step-by-step Explanation: We put x = 0; then y = 6; y-intercept of the line is (0,6).

For the slope: 4y = 24 - 14x; then, y = (-7/2)x + 6; the slope is -7/2.

erica [24]2 years ago

3 0

Answer: The answer would be letter B. -7/2; 6

Use the slope-intercept form y = m x + b to find the slope m and y-intercept b .

Slope:

− 7 /2

y-intercept:

( 0 , 6)

Step-by-step explanation: You have to find the slope and y-intercept

Find the slope and y-intercept of the line.

14x + 4y = 24

Find the Slope and y-intercept

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The circumference of a circle is 47.1 and the diameter of the circle is 15. Which best represents the value of π? 47.1/15 7.54/7

Vlad1618 [11]

Answer: 47.1/15

Step-by-step explanation:

We define Circumference by C= pie X D[diameter]

Hence pie= C/ D= 47.1/15

3 0

3 years ago

A standard number cube is tossed. Find the following probability. P(greater than 4 or odd)

lorasvet [3.4K]

A standard cube has 6 possible outcomes. But since we want to find P(4+ or odd), the outcomes become more narrow.
So:
6 outcomes -> 1, 2, 3, 4, 5, 6

But we want to find 4+
So:
4+ = 4, 5, 6

We also want to find all odd possibilities.
So:
odd = 1, 3, 5

As you can see, there is a 5 in both the 4+ and the odd numbers so 5 will only be counted once.
P(4+ or odd) = 1, 3, 4, 5, 6

So the probability of having an outcome that is P(4+ or odd) is:
5/6 or 0.8333 or 83.33%

Hope I helped!

8 0

3 years ago

Read 2 more answers

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$