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2 years ago

13

Television sizes are usually described by the length of their diagonal measure. What would be the listed size of the Tv whose wi

dth is 45inches and height is 26 inches

1 answer:

wel2 years ago

7 0

Answer:

50 or 55

Step-by-step explanation:

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What is the value of x in the equation −x = 4 − 3x + 6?<br><br> 5<br> 10<br> −5<br> −10

ddd [48]

Combine like terms

-x = 4 + 6 - 3x
-x = 10 - 3x

Isolate the x, add 3x to both sides

-x (+3x) = 10 - 3x (+3x)

-x + 3x = 10

Simplify. Combine like terms

-x + 3x = 10

2x = 10

Isolate the x, divide 2 from both sides

2x/2 = 10/2

x = 10/2

x = 5

x = 5, or A is your answer

hope this helps

8 0

3 years ago

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F(n)=5.(-2)n-1<br>Complete the recursive formula of f(n).

Alex73 [517]

Answer:

a(n) = $(-2)(a_{n-1})$

$a_{1}=5$

Step-by-step explanation:

The given expression is in the form of the explicit formula of a geometric sequence.

f(n) = $a(r)^{n-1}$

Where 'a' = First term of the sequence

r = common ratio

Recursive formula of a geometric sequence is,

a(n) = $(a_{n-1}).(r)^{n-1}$

a(n) = $(-2)(a_{n-1})$

Where, $a_{1}=5$

So the recursive formula will be a(n) = $(-2)(a_{n-1})$

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3 years ago

How are corresponding side lengths of two similar figures related

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3 years ago

PLEASE HELP! THIS IS DUE TOMORROW! Much appreciated.

denis23 [38]

Answer:

Step-by-step explanation:

1a) angle x and angle y are corresponding angles. Both angles lie on the same side of the transversal. Since the lines are parallel, the angles are equal.

1b) angle x and angle y are interior angles on the same side of the transversal. Since the lines are parallel, the angles are equal supplementary.

1c) angle x and angle y are corresponding angles. Both angles lie on the same side of the transversal. Since the lines are parallel, the angles are equal.

1d) angle x and angle y are alternate interior angles. They are between the parallel lines and alternate sides of the transversal. Since the lines are parallel, the angles are equal.

3 0

3 years ago

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If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution.</em>

Set <em>u</em>: $\displaystyle u = 4x^{-2}$
[<em>u</em>] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

<u>Step 3: Integrate Pt. 2</u>

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago