Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
Answer:
C
Step-by-step explanation:
Just checked this is correct
Answer:
1.5
Step-by-step explanation:
picture
A. 9
B. 24
C. 6
D. 16
Step-by-step explanation:
Given ratios are;
A. 2 : 3 = 6 : x
Product of mean = Product of extreme
Dividing both sides by 2
B. 4 : 7 = x : 42
Product of mean = Product of extreme
Dividing both sides by 7
C. 2x : 48 = 3 : 12
Product of extreme = Product of mean
Dividing both sides by 24
D. 12 : 15 = x : 20
Product of mean = Product of extreme
Dividing both sides by 15
