5 , 15 , 45 , 135 find the common ratio

Mathematics

1 answer:

Alisiya [41]3 years ago

4 0

The answer to ur question is number 3

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Half of the students in Max's class volunteer at the local community center.Fifteen students do not volunteer.If there are 12 bo

yulyashka [42]

18 girls
Half of the students volunteer
15 don't -- so the other half must be 15 as well making there 30 students in the class.
If 12 are boys, then 30(students in class) - 12 (boys) = 18 girls

7 0

2 years ago

Assume there are 365 days in a year.

Dahasolnce [82]

The chance of student 1's birthday being individual is 365/365 or 100%.
Then the chance of student 2's birthday being different is 364/365.
Then it's narrowed down to 363/365 for student 3 and so on until you get all 10 students.
If you multiply all these values together, the probability would come out at around 0.88305182223 or 0.88.

To get all the same birthday you'd have to the chance of one birthday, 1/365 and multiply this by itself 10 times. This will produce a very tiny number. In standard form this would be 2.3827x10'-26 or in normal terms: 0.23827109210000000000000000, so very small.

4 0

3 years ago

3. A kite is aloft at the end of a 1500 foot string. The string make an angle of 43° with the

sineoko [7]

Answer:

$h= 1500\,*\,sin(43^o)$

Step-by-step explanation:

Notice that there is a right angle triangle formed with sides as follows:

hypotenuse is the actual 1500 ft string. The acute angle 43 degrees is opposite to the segment that represents the height of the kite from the ground. Therefore, the trigonometric ratio that we can use to find that opposite side to the given angle, is the sine function as shown below:

$sin(43^o) = \frac{opposite}{hypotenuse} \\sin(43^o) = \frac{opposite}{1500}\\opposite = 1500\,*\,sin(43^o)\\h= 1500\,*\,sin(43^o)$