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Dvinal [7]
3 years ago
14

5 , 15 , 45 , 135 find the common ratio

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0
The answer to ur question is number 3
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On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
Alenkinab [10]

Total distance = 380 miles

Let the time & distance of 1st day be = t1 & d1 respectively

Distance = Speed x Time

For second day : d2 = s2 x t2 ; d2 = 60 x t2

For first day : d1 = s1 x t1 ; d1 = 40 x t1

Given : d1 = d2 + 20 & t1 = t2 + 2 , putting these values in d1

d2 + 20 = 40 (t2 + 2)

Putting value of d2 ,

60 t2 + 20 = 40 t2 + 80

60 t2 - 40 t2 = 80 - 20

20t2 = 60

t2 = 60 / 20 ; t2 = 3

So, t1 = 3+2 = 5

Hence : d1 = 40 x 5 = 200 ; d2 = 60 x 3 = 180

Therefore , Total Distance = 200 + 180 = 380

6 0
3 years ago
Evaluate the expression by using the given value of the variables.
yaroslaw [1]
Y ÷ 2 • 4 – 10 ÷ x + 6 where <span>x = 5 and y = 16
</span>
Plug x=5 and y= 16 in the above expression:
16/ 2 *4 - 10/ 5 + 6
= 8 *4 - 2 + 6
= 32 -2 + 6
= 30 + 6
= 36.

c. 36 is the correct answer~

8 0
3 years ago
I'm ABC, the measure of
Andreas93 [3]

Answer: D,E,F,G

It's self explanitory

3 0
2 years ago
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A car travels at a speed of 64 km/h. Find the distance travelled in 4½ hours. ​
nordsb [41]
Answer: 160m

Explanation: I hope this helps <3
6 0
2 years ago
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Elis [28]

Answer: 151 books

Step-by-step explanation: 243-65-59+32=151

4 0
2 years ago
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