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zmey [24]
2 years ago
14

Determine what number to multiply the first equation by to form opposite terms for the x-variable. 2/5 x + 6y = -10 –2x – 2y = 4

0 Multiplying the first equation by will create opposite x terms.
Mathematics
2 answers:
katovenus [111]2 years ago
7 0

Answer: 5

Step-by-step explanation: edge 2021

m_a_m_a [10]2 years ago
6 0

Answer:

5

Step-by-step explanation:

Just finished

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Crystal earns $5.50 per hour mowing lawns.how much does crystal earn if she works 3 hours and 45 minutes
Deffense [45]
Your question does not make sense unless you can estimate but the answer would be 20.625

Work:
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3 years ago
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
Delvig [45]

Answer:

Step-by-step explanation:

a) We would set up the hypothesis test.

For the null hypothesis,

p = 0.25

For the alternative hypothesis,

p ≠ 0.25

b) The test statistic to be used is the z test. The formula is

z = (P - p)/√pq/n

c) Considering the population proportion, probability of success, p = 0.25

q = probability of failure = 1 - p

q = 1 - 0.25 = 0.75

Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 141

n = number of samples = 600

P = 141/600 = 0.235

Therefore

z = (0.235 - 0.25)/√(0.25 × 0.75)/600 = - 0.85

d) Recall, population proportion, p = 0.25

The difference between sample proportion and population proportion is 0.25 - 0235. = 0.015

Since the curve is symmetrical and it is a two tailed test, the p for the left tail is 0.25 - 0.015 = 0.235

the p for the right tail is 0.25 + 0.015 = 0.265

These proportions are lower and higher than the null proportion. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score in the left tail 0.198

We would double this area to include the area in the right tail of z = 0.85. Thus

p = 0.198 × 2 = 0.396

e) Since alpha, 0.01 < than the p value, 0.396, then we would fail to reject the null hypothesis.

f) In a sample of 600 cars, we would observe a sample proportion of 0.015 or more away from 0.25 about 39.6% of the time by chance alone. Therefore, the sample result is not statistically significant because it could occur in 39.6% of the time by chance alone.

8 0
3 years ago
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