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ELEN [110]
2 years ago
8

Find the missing side of each triangle. Round your answers to the nearest tenth if necessary.

Mathematics
2 answers:
ira [324]2 years ago
8 0

Answer:

Step-by-step explanation:

Kisachek [45]2 years ago
8 0
<h2>>> Answer </h2>

___________

\:

\boxed{ \rm{answer \: by \: { \boxed{ \rm{☆HayabusaBrainly}}}}}

  • Step by step :

x² = (14,4)² - 9²

x² = 207,36 - 81

x² = 126,36

x = 11,2

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In a rational function, is the horizontal shift represented by the vertical asymptote?
ziro4ka [17]
<h3>Short Answer: Yes, the horizontal shift is represented by the vertical asymptote</h3>

A bit of further explanation:

The parent function is y = 1/x which is a hyperbola that has a vertical asymptote overlapping the y axis perfectly. Its vertical asymptote is x = 0 as we cannot divide by zero. If x = 0 then 1/0 is undefined.

Shifting the function h units to the right (h is some positive number), then we end up with 1/(x-h) and we see that x = h leads to the denominator being zero. So the vertical asymptote is x = h

For example, if we shifted the parent function 2 units to the right then we have 1/x turn into 1/(x-2). The vertical asymptote goes from x = 0 to x = 2. This shows how the vertical asymptote is very closely related to the horizontal shifting.

7 0
3 years ago
Solve for x in terms of r, s and t : s=2x+t/r
Anna007 [38]

For this case we have the following equation:

s = \frac {2x + t} {r}

We must clear the value of the variable "x" as a function of r, s and t:

If we multiply by "r" on both sides of the equation we have:

rs =2x + t

If we subtract "t" on both sides of the equation we have:

rs-t = 2x

If we divide by "2" on both sides of the equation we have:

x = \frac {rs-t} {2}

Thus, the value of the variable "x" is:

x = \frac {rs-t} {2}

Answer:

x = \frac {rs-t} {2}

4 0
3 years ago
Help! I PUT 50 POINTS!
artcher [175]

Answer:

i-4 1/8

ii- 2 3/100

iii- 10 123/1000

iv- 292/625

Step-by-step explanation:

...

4 0
3 years ago
The circumference of the circle is increasing at a rate of 0.5 meters per minute. What's the rate of change of the area of the c
morpeh [17]

Answer:

The rate of change of the area of the circle when the radius is 4 meters = 2 meters²/minute ⇒ answer 4

Step-by-step explanation:

* Lets revise the chain rule in the derivative

- If dy/da = m and dx/da = n, and you want to find dy/dx

∴ dy/dx = dy/da ÷ dx/da = m ÷ n = m/n

* In our problem we have

- The rate of increasing of the circumference dC/dt = 0.5 meters/minute

- We need the find the rate of change of the area of the circle

 when the radius is 4 meters

- The common element between the circumference and the area

 of the circle is the radius of the circle

* We must to find dC/dr and dA/dr and use the chain rule to

 find dA/dr

- Find the rate of change of the radius dr/dt

∵ C = 2πr

- Find the derivative of C with respect to r

∴ dC/dr = 2π ⇒ (1)

∵ dC/dt = 0.5 meters/minute ⇒ (2)

- Divide (1) by (2) to get dr/dt by using chain rule

∵ dC/dt ÷ dC/dr = 0.5 ÷ 2π

∴ dC/dt × dr/dC = 0.5 × 1/2π ⇒ cancel dC together and change

   0.5 to 1/2

∴ dr/dt = 1/2 × 1/2π = 1/4π ⇒ (3)

- Find the rate of change of the area dA/dt

∵ A = πr²

- Find the derivative of A with respect to r

∴ dA/dr = 2πr

∵ r = 4

∴ dA/dr = 2π(4) = 8π ⇒ (4)

- Multiply (4) by (3) to get dA/dt by using chain rule

∵ dA/dr × dr/dt = 8π × 1/4π ⇒ divide 8 by 4 and cancel π

∴ dA/dt = 2 meters²/minute

* The rate of change of the area of the circle when the radius is

  4 meters = 2 meters²/minute

3 0
3 years ago
Any highly recommended math word problem solving app.... please​
serg [7]

Owl Hat is a tutor and next-level math solver at your fingertips.

8 0
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