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DaniilM [7]
3 years ago
11

A square target is shown. A dart is dropped randomly onto the target. The dart is equally kely to hit any spot on the target

Mathematics
1 answer:
almond37 [142]3 years ago
3 0

Answer:

23/5.................

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They're parallel because they have the same slope.
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It seems simple I just don't know what type of answer it's asking for.
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Each unit on the grid stands for one miles determine two ways to calculate the distance from josie's house to annies
Novosadov [1.4K]
I encountered this problem before but it had an accompanying image and list of answer choices.

I'll attach the image and include the list of options. 

Each unit on the grid stands for one mile. Determine two ways to calculate the distance from Josie's house to Annie's house.
A) Distance Formula and Slope Formula
B) Midpoint Formula and Slope Formula
C) Distance Formula and Midpoint Formula
<span>D) Distance Formula and Pythagorean Theorem
</span>
My answer is: D.) Distance formula and Pythagorean Theorem.

When looking at the image, I can visualize a right triangle. I'll simply get the measure of the long and short legs and solve for the hypotenuse. 
Since the distance formula is derived from the Pythagorean theorem, it can be used to determine the distance from Josie's house to Annie's house.

8 0
2 years ago
Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

e) E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

f) E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

4 0
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A pair of hiking boots originally priced at $170 is on sale for 10% off. What is the sale price of the boots?
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The sale price of the hiking boots is $153
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