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Answer:
- The lowest value of the confidence interval is 0.5262 or 52.62%
- The highest value of the confidence interval is 0.5538 or 55.38%
Step-by-step explanation:
Here you estimate the proportion of people in the population that said did not have children under 18 living at home.It can also be given as a percentage.
The general expression to apply here is;
where ;
p=sample proportion
n=sample size
z*=value of z* from the standard normal distribution for 95% confidence level
Given;
n=5000
<u>Find p</u>
From the question 54% of people chosen said they did not have children under 18 living at home
<u>To calculate the 95% confidence interval, follow the steps below;</u>
- Find the value of z* from the z*-value table
The value of z* from the table is 1.96
- calculate the sample proportion p
The value of p=0.54 as calculated above
- Find p(1-p)
- Find p(1-p)/n
Divide the value of p(1-p) with the sample size, n
- Find the square-root of p(1-p)/n
- Find the margin of error
Here multiply the square-root of p(1-p)/n by the z*
The 95% confidence interval for the lower end value is p-margin of error
The 95% confidence interval for the upper end value is p+margin of error
Answer:
A.
Step-by-step explanation:
If
AND
y = x + 7, then by the transitive property of equality:
We can solve for the values of x by getting everything on one side of the equals sign and then solving for x:
We can factor out the common x to get:
x(x + 1) = 0
which tells us by the Zero Product Property that either
x = 0 and/or x + 1 = 0 and x = -1
We are expecting 2 solutions for x since this is a second degree polynomial. We will sub both -1 and 0 into y = x + 7 to solve for the corresponding values of y
y = 0 + 7 so
y = 7 and the coordinate is (0, 7)
y = -1 + 7 so
y = 6 and the coordinate is (-1, 6)