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topjm [15]
3 years ago
15

Factor the trinomial: 3x2 + 13x + 12

Mathematics
1 answer:
yarga [219]3 years ago
8 0

Answer:

Step-by-step explanation:

(3x + 4)(x + 3)

3x^2 + 9x + 4x + 12

3x^2 + 13x + 12

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A CD usually sells for $17.00. If the CD is 20% off, and sales tax is 5%, what is the total price of the CD, including tax?
Vedmedyk [2.9K]

Answer:

$14.28

Step-by-step explanation:

If the CD is $17 and is have a 20% off then you multiply .20 and 17 to get the amount that is off. Subtract that answer from 17 and you should get $13.60. That is the cost of the CD WITHOUT tax. To apply the tax, you multiply the cost and 0.05 (5%) to get 0.68. 0.68 is the tax cost. To get the entire cost of the CD, you add 0.68 (tax) and price (13.60) and get $14.28.

5 0
3 years ago
Read 2 more answers
A sweater is marked down from an original price of $45 to $33.75. By what percent has the original price of the sweater been mar
BlackZzzverrR [31]
<span>33.75/45.00 x 100 = 75%
This means you are paying 75% of the original.

That means that the price has been marked down by 100-75 = 25% because that is how much of the original you are NOT paying.

Therefore, the answer is 25%. </span>
6 0
3 years ago
Read 2 more answers
Answer quickly please &lt;3
sertanlavr [38]

Answer:

x is greater than -5

Step-by-step explanation:

3 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
2 years ago
What is the 8th term in the sequence? 1, 2, 4, 7​
MAVERICK [17]

Answer: 29

explanation: you add 1 to get 2, you then add 2 to get 4, then 3 to get to 7, then 4 to get to 11, then 5 to get to 16, then 6 to get to 22, then 7 to get to 29

8 0
3 years ago
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