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3 years ago

Factor the trinomial: 3x2 + 13x + 12

Mathematics

1 answer:

yarga [219]3 years ago

8 0

Answer:

Step-by-step explanation:

(3x + 4)(x + 3)

3x^2 + 9x + 4x + 12

3x^2 + 13x + 12

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A CD usually sells for $17.00. If the CD is 20% off, and sales tax is 5%, what is the total price of the CD, including tax?

Vedmedyk [2.9K]

Answer:

$14.28

Step-by-step explanation:

If the CD is $17 and is have a 20% off then you multiply .20 and 17 to get the amount that is off. Subtract that answer from 17 and you should get $13.60. That is the cost of the CD WITHOUT tax. To apply the tax, you multiply the cost and 0.05 (5%) to get 0.68. 0.68 is the tax cost. To get the entire cost of the CD, you add 0.68 (tax) and price (13.60) and get $14.28.

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3 years ago

Read 2 more answers

A sweater is marked down from an original price of $45 to $33.75. By what percent has the original price of the sweater been mar

BlackZzzverrR [31]

<span>33.75/45.00 x 100 = 75%
This means you are paying 75% of the original.

That means that the price has been marked down by 100-75 = 25% because that is how much of the original you are NOT paying.

Therefore, the answer is 25%. </span>

6 0

3 years ago

Read 2 more answers

Answer quickly please <3

sertanlavr [38]

Answer:

x is greater than -5

Step-by-step explanation:

3 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

What is the 8th term in the sequence? 1, 2, 4, 7

MAVERICK [17]

Answer: 29

explanation: you add 1 to get 2, you then add 2 to get 4, then 3 to get to 7, then 4 to get to 11, then 5 to get to 16, then 6 to get to 22, then 7 to get to 29

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3 years ago