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erastova [34]
3 years ago
8

What is the correct factorization of -3x^2+16x+35

Mathematics
2 answers:
Mashutka [201]3 years ago
8 0

Answer:

I love algebra anyways

The ans is in the picture with the  steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

bekas [8.4K]3 years ago
4 0
−(3x^2−16x−35)

−(3x^2+5x−21x−35)

−(x(3x+5)−7(3x+5))

−(3x+5)(x−7)
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What is the present value of an investment that will be worth $6000 at the end of five years? Assume an APR of 6% compounded mon
musickatia [10]

Answer:

4448.23

Step-by-step explanation:

AV=PV(1+\frac{i}{n})^{nt}\\\\6000=PV(1+\frac{.06}{12})^{5*12}\\\\6000=PV*1.3488\\\\PV= 4448.23

4 0
3 years ago
Will give BRAINLIEST
likoan [24]

Answer:

Quadrant 1 (1,5)

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Kyle is stringing a necklace with beads he puts black beads on 5/8 of the string and white beads on 1/4 of the string Kyle think
Alexeev081 [22]

Answer:Kyle’s claim is not reasonable

Step-by-step explanation:

Total length of the string of the necklace that Kyle covered with black beads is 5/8.

Total length of the string of the necklace that Kyle covered with white beads is 1/4.

Total length of the string of the necklace that Kyle covered with black beads and white beads is would be

1/4 + 5/8 = 7/8 = 0.875

Kyle thought that he will cover 6/12 of the string with beads. 6/12 = 0.5

It means that he covered more than 6/12. Kyle's claim was wrong

3 0
3 years ago
Let f ( x ) = 2 x − 1 , g ( x ) = 3 x , and h ( x ) = x ^2 + 1 , what is h( h ( 5) ) ?
strojnjashka [21]
First you would solve for h(5) by plugging in 5 as your x, then solving it.

h(5) = 5^2 + 1
h(5) = 25 + 1
h(5) = 26

Next you would multiply the 26 by the individual h, which is basically h(1).

h(1) = 1^2 + 1
h(1) = 2

Lastly you multiply your h(1) value by the h(5) value to get your answer.

h(1) • h(5) = 26 • 2
h[h(5)] = 52
7 0
4 years ago
Review the graph of function f(x).
s344n2d4d5 [400]

The two limits when x tends to zero are:

\lim_{x \to \ 0^-}  f(x) = 1\\\\ \lim_{x \to \ 0^+}  f(x) = 0

<h3 /><h3>How to get the limits when x tends to zero?</h3>

Notice that we have a jump at x = 0.

Then we can take two limits, one going from the negative side (where we will go along the blue line)

And other from the positive side (where we go along the orange line).

We will get:

\lim_{x \to \ 0^-}  f(x) = 1\\\\ \lim_{x \to \ 0^+}  f(x) = 0

Notice that the two limits are different, that means that the function is not a continuous function.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

6 0
3 years ago
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