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nikdorinn [45]
3 years ago
7

PLS JELP NOWOWOWIWOW

Mathematics
1 answer:
Ratling [72]3 years ago
3 0

Answer:

last option. absolute value doesnt matter whether it is positive or negative

Step-by-step explanation:

You might be interested in
The area of a rectangular pool was 120square meters. If the long side in 7 meters plus a number and the width is 6 meters. What
NeX [460]

Answer:

The value of the variable=13 meters

Step-by-step explanation:

Step 1

Express the dimensions of the pool

Length=7+x

width=6

Step 2

Express the area of a rectangle as shown;

A=L×W

where;

A=area of a rectangle

L=length of the rectangle

W=width of the rectangle

In our case;

A=120 m²

L=x+7

W=6

replacing in the equation;

120 m²=(x+7)×6

120=6 x+42

6 x+42=120

6 x=120-42

6 x=78

x=78/6

x=13

The value of the variable=x=13 meters

8 0
3 years ago
What is the answer to this question? Please help and make it quick!
KonstantinChe [14]

Answer:

i believe it would be the las one im pretty sure but not 100% so hope it works and let me know if im right or not but again hope this helps

step-by-step explanation:

4 0
3 years ago
1) y=-3x + 4 y = 3x - 2 (1,1)​
puteri [66]

Answer:

y=3x-2

Step-by-step explanation:

your question didn't have any instructions so this might not be what you're looking for

set them equal to each other

-3x+4=3x-2

-3x-3x=-2-4

-6x=-6

x=1

plug in x=1

y=3(1)+4   =7

y=3(1)-2   =1

so, when x=1, y=1 in the expression y=3x-2

7 0
3 years ago
We wish to give a 90% confidence interval for the mean value of a normally distributed random variable. We obtain a simple rando
coldgirl [10]

Answer: (9.27025,\ 11.12975)

Step-by-step explanation:

Given : Sample size : n= 9

Degree of freedom = df =n-1 =8

Sample mean : \overline{x}=10.2

sample standard deviation : s= 1.5

Significance level ; \alpha= 1-0.90=0.10

Since population standard deviation is not given , so we use t- test.

Using t-distribution table , we have

Critical value = t_{\alpha/2, df}=t_{0.05 , 8}=1.8595

Confidence interval for the population mean :

\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

90% confidence interval for the mean value will be :

10.2\pm (1.8595)\dfrac{1.5}{\sqrt{9}}

10.2\pm (1.8595)\dfrac{1.5}{3}

10.2\pm (1.8595)(0.5)

10.2\pm (0.92975)

(10.2-0.92975,\ 10.2+0.92975)

(9.27025,\ 11.12975)

Hence, the 90% confidence interval for the mean value= (9.27025,\ 11.12975)

6 0
3 years ago
Which expression is equivalent to<br> (5^-2)(5^-1)<br> A. -1/125<br> B. -1/5<br> C.1/125<br> D.1/5
alexandr402 [8]

Answer:is 5 ^ -2 ????

Step-by-step explanation:

8 0
3 years ago
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