Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
Answer:
1/ (1000x^3)
Step-by-step explanation:
yes
Answer:
I'm pretty sure it is D I'm not 100% sure though... sorry if it is wrong
She will be able to cover 469.875 meters
Answer:
Step-by-step explanation: let 2:3:5:8 be 2x,3x,5x,8x respectively .
*angles in a quadrilateral is 360 degree
*2x+3x+5x+8x=360
*18x=360
*x=360/18
*x=20
now substitute x in these:
2x=2x20=40
3x=3x20=60
5x=5x20=100
8x=8x20= 160
so these are the following angles: 40,60,100 and 160
