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3 years ago

SOMEBODY HELP ME I NEED THE ANSWER AND DONT GIVE ME A LINK DOES THE LINK IS FAKE !!!!

Mathematics

2 answers:

Keith_Richards [23]3 years ago

8 0

Answer:

Step-by-step explanation:

soldi70 [24.7K]3 years ago

7 0

Answer:

Step-by-step explanation:

Now I can not be 100% sure since I can not see the chart, but I can go off of logic. So let´s get started

First we can eliminate answer B. Answer B does not make ANY sense. Why would the number 3 make a difference.

Now answer A and D. These answers are basically the same. So if one is true, the other is as well. For D, if it were the same number, just negative and positive, the sum would be 0.

So this makes A and D true

Answer C is backed up by answer D as well. They can only be the same distance if one is positive and the other is negative

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AleksAgata [21]

1) 2x 2) 6x 3) -4 There you go

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3 years ago

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H(x+1)=x^2-4 evaluate function by substuting x+1

zalisa [80]

Answer:

h(x + 1) = (x+3)(x-1)

Step-by-step explanation:

Simply plug the value of x+1 into the equation for x.

h(x) = x^2 - 4

h(x + 1) = (x + 1)^2 - 4

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4 years ago

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Homework problem #7: 24567389+35432611=what there is soo much regrouping, could someone show me how to do it?

Natasha_Volkova [10]

Answer:

$24567389+35432611 =60000000$

Step-by-step explanation:

Given

$24567389+35432611 =$

Required

Solve

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

<em>The numbers in parentheses are carried from previous sum</em>

Start from the right

$9 + 1 = 10 \to$ Write 0, carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

$8 + 1 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0

$6 +3 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0

$7+2 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0

$6 +3 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0 0

$5 +4 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0 0 0

$4 +5 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0 0 0 0

$2 +3 + (1) = 6 \to$ Write 6

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

6 0 0 0 0 0 0 0

Hence:

$24567389+35432611 =6 0 0 0 0 0 0 0$

8 0

3 years ago

Part A: If (7exponent2)exponentX = 1, what is the value of X? Explain your answer.

yKpoI14uk [10]

Answers:
Part A: The value of x must be 0
Part B: The value of x can be any real number

----------------------------------------------------------------

Explanation:

Part A) We have the equation (7^2)^x = 1 which simplifies to 7^(2x) = 1. The only way to get the left side equal to the right side is to have the exponent of 2x equal zero. If 2x = 0, then x = 0. So that's why x = 0 is the only solution here.

--------------

Part B) Similar to part A above, but the exponent is slightly different now. We have (7^0)^x = 1 which turns into 7^(0*x) = 1. The exponent 0*x is really 0 no matter what x is. We can plug in any real number we want for x and the left side will always be 1. This is why the solution set to this equation is the set of all real numbers.

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3 years ago

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dmitriy555 [2]

Answer:

Step-by-step explanation:

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