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muminat
3 years ago
11

80 is ⅒ of ____. HELP ME

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer:

800

Step-by-step explanation:

If you multiply 1 tenth by 80 you will get 800 over 1.

800/1

800/1 = 800.

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Twenty-six students apply to serve as an usher at a school function. Eight of the those applying are freshmen, 7 are sophomores,
Gelneren [198K]

Answer:

d

Step-by-step explanation:

from usatestprep:

The situation is not an example of uniform probability because freshmen, sophomores, juniors, and seniors do not have equal probabilities of being selected.; Uniform probability → equal probability of being selected

P(freshman) =  

8/

26

; P(sophomore) =  

7 /

26

; P(junior) =  

6 /

26

; P(senior) =

5 /

26

; unequal probabilities → not uniform

6 0
3 years ago
Read 2 more answers
Jolly Middle School is building a park, in the shape of a square, with an area of 256 square feet. How much fence do they need t
kumpel [21]

Answer:

well that would mean that the perimeter is 256/4 and that is 64

Step-by-step explanation:

i think the answer is 64

6 0
3 years ago
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1 1/3 ÷ 5/6 qual e a resposta dessa pergunta<br><br><br>​
Korvikt [17]

Answer: 1 9/15

Step-by-step explanation:

I can’t speak Spanish

6 0
3 years ago
Help please ASAP please I’ll mark you as brainlister
storchak [24]

Answer:

a = 4

Step-by-step explanation:

\sin(theta)  =  \frac{opposite}{hypotenuse}

\cos(theta)  =  \frac{adjacent}{hypotenuse}

\tan(theta)  =  \frac{opposite}{adjacent}

hypotenuse = a

opposite = 2√3

adjacent = b

theta = 60°

the best formula to use is the first formula cause we have all the values to substitute in it in order to find the value of a

\sin(60)  =  \frac{2 \sqrt{3} }{a}

\frac{2 \sqrt{3} }{ \sin(60) }  = a

4 = a

a = 4

4 0
3 years ago
during a 500-meter race, a runner ran the first 400 meters in 1 minute and 25 seconds.she finished the race i 2 minutes and 15 s
mart [117]

She ran the last 100 meters in 2:15 -1:25 = 0:50, so her average speed was

... (100 m)/(50 s) = 2.0 m/s

6 0
3 years ago
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