Find the area of the shape below. Plz help!!!

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

5 0

Answer:

A = 108 units²

Step-by-step explanation:

The area (A) of a trapezium is calculated as

A = $\frac{1}{2}$ h (b₁ + b₂ )

where h is the height between the 2 bases and b₁, b₂ are the parallel bases

Here h = 24 , b₁ = 8 , b₂ = 1 , then

A = $\frac{1}{2}$ × 24 × (8 + 1) = 12 × 9 = 108 units²

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The center of a circle lies on the line y = 4x + 1 and is tangent to the x-axis at (−3,0) . What is the equation of the circle i

Hunter-Best [27]

Answer:

$(x+3)^2+(y+11)^2=121$

Step-by-step explanation:

Consider a sketch of the problem as shown in the picture, where:

Blue line is given by y = 4x + 1.
Point B is the center of the circle.
Point A is (-3, 0).

Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.

So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.

Since the <em>general equation of the circle</em> of radius lenght r centered at (h, k) is given by

$(x-h)^2+(y-k)^2=r^2$