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3 years ago

Which is larger 16.455 or 16.45

Mathematics

2 answers:

Feliz [49]3 years ago

8 0

<span>16.455 is larger than 16.45

hope that helps</span>

Sveta_85 [38]3 years ago

8 0

16.455 is larger Hope this helps! ;D

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Evaluate the question?

Snezhnost [94]

Since all you’re saying is evaluate ∫12–2
I’m assuming the answer would be 1/(1+x)(1-x)

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3 years ago

Read 2 more answers

5a^5+60a^5-45a^4/15a^4

Artemon [7]

So basically, for this you would be combining like-terms and simplifying. This will give you -3a^8+65a^5

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4 years ago

Tanner is getting balloons for his mother's birthday party. He wants each balloon string to be 6 feet long. At the party store,

melisa1 [442]

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3 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0

3 years ago

At the start of the recovery period, the waterbuck population contained only 140 individuals. The population had 0.67 births per

Sergio [31]

Answer:

the intrinsic growth rate of the population = 0.67 - 0.06 = 0.61 or 61%

Step-by-step explanation:

since populations increase exponentially, the same will happen here

in 5 years the population should be:

P₅ = P₀e°⁶¹ˣ⁵ = 140e°⁶¹ˣ⁵ = 2,956.15 ≈ 2,956

in 10 years the population will be:

P₁₀ = P₀e°⁶¹ˣ¹⁰ = 140e°⁶¹ˣ¹⁰ = 62,420.09 ≈ 62,420

when you are using exponential growth rates, we have to assume that r will always remain constant

6 0

3 years ago