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lidiya [134]
4 years ago
8

The boiling point of water (H2O) is 100 °C. Which of the following best predicts the boiling point of hydrogen sulfide (H2S)? (5

points)
Chemistry
1 answer:
Rufina [12.5K]4 years ago
6 0

Answer:

Boiling point of H2S is (-60.2 C°)

Explanation:

This is very less than water because hydrogen bonding is present in water that is absent in H2S

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Select all of the physical properties of matter
Vera_Pavlovna [14]

Answer:

A) solubility

B)luster

D)Density

F)magnetism

Explanation:

A physical property is one that tells us everything about what a substance is when no change is is occurring to its constituent.

Such properties can be observed with our senses or instruments or pieces of apparatus.

  • Examples are luster, density, solubility, taste, odor, color, melting point, boiling point etc.
3 0
3 years ago
The chemical reaction shown here, in which a large molecule is broken down into the smaller parts that make it up, is called a _
Triss [41]
I believe such reactions are called decomposition reactions. Decomposition reactions are reactions that involve breaking down a compound into smaller compounds or individual elements. They involve input of energy in the form of heat, electricity or light to break down the compounds. When light is used the reaction is referred to as photo decomposition while when heat is used the reaction is thermal decomposition reaction e.t.c. The general form of the reaction is AB = A + B.
8 0
3 years ago
Read 2 more answers
How many milliliters of 0.258M NaOH are required to completely neutralize 2.00 g of acetic acid HC2H3O2?
madam [21]

Answer:

0.129 L = 129.0 mL.

Explanation:

  • NaOH neutralizes acetic acid (CH₃COOH) according to the balanced reaction:

<em>NaOH + CH₃COOH → CH₃COONa + H₂O.  </em>

  • According to the balanced equation: 1.0 mole of NaOH will neutralize 1.0 mole of CH₃COOH.  

<em>no. of moles of CH₃COOH = mass/molar mass </em>= (2.0 g)/(60 g/mol) = <em>0.033 mole.  </em>

<em> </em>

  • For NaOH:

no. of moles = (0.258 mol/L)(V)

  • At neutralization: no. of moles of NaOH = no. of moles of CH₃COOH  

∴ (0.258 mol/L)(V) = 0.033 mole

<em>∴ The volume of NaOH</em> =  (0.033 mole)/(0.258 mol/L) = <em>0.129 L = 129.0 mL.</em>

8 0
4 years ago
Which of the following is the correct scientific notation for 0.0000782 g?
Dominik [7]
The correct scientific notation is 7.82 x 105 g
7 0
3 years ago
Read 2 more answers
A student dissolves of 15 g aniline in of a solvent with a density of . The student notices that the volume of the solvent does
VikaD [51]

The given question is incomplete. The complete question is ;

A student dissolves of 15 g aniline in 200 ml of a solvent with a density of 1.05 g/ml. The student notices that the volume of the solvent does not change when the aniline dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits.

Answer: The molarity is 0.81 M and molality is 0.82 m

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute  

V_s = volume of solution in ml = 200 ml

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol

Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.16\times 1000}{200}=0.81M

Thus molarity is 0.81 M

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n\times 1000}{W_s}

where,

n = moles of solute

W_s = weight of solvent in g

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol

Mass of solution = Density\times Volume=1.05g/ml\times 200ml=210g

mass of solvent = mass of solution - mass of solute = (210 - 15) g = 195 g

Now put all the given values in the formula of molality, we get

Molality=\frac{0.16\times 1000}{195g}=0.82mole/kg

Therefore, the molality of solution is 0.82m

3 0
3 years ago
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