Funnel is used to filter or to deliver liquid from one container to another
Producer, Primary consumers, Secondary consumers and Tertiary consumers.
A.
Cr⁺¹ + Sn⁺⁴ ⇒ Cr⁺³ + Sn⁺²
Cr⁺¹ ⇒ Cr⁺³ + 2e⁻
The half-reaction of oxidation: chrome is an electron donor, losses 2 electrons ie it is oxidized
2e⁻ + Sn⁺⁴ ⇒ Sn⁺²
The half-reaction of reduction: tin is an electron acceptor, receives 2 electrons, ie it is reduced
b.
3Hg⁺² + 2Fe ⇒ 3Hg + 2Fe⁺³
2Fe ⇒ 2Fe⁺³ + 6e⁻
The half-reaction of oxidation: iron is an electron donor, losses 3 electrons ie it is oxidized
6e⁻ + 3Hg⁺² + ⇒ 3Hg
The half-reaction of reduction: mercury is an electron acceptor, receives 2 electrons, ie it is reduced
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c.
2As + 3Cl</span>₂ ⇒ 2AsCl₃
2As ⇒ 2As⁺³ + 6e⁻
The half-reaction of oxidation: arsenic is an electron donor, losses 3 electrons ie it is oxidized
6e⁻ + 3Cl₂ ⇒ 6Cl⁻
The half-reaction of reduction: chlorine is an electron acceptor, receives 1 electron, ie it is reduced
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d.
NaBr + Cl</span>₂ ⇒ NaCl + Br₂<span>
</span>2Br⁻ ⇒ Br₂ + 2e⁻
The half-reaction of oxidation: bromine is an electron donor, losses 1 electron ie it is oxidized
2e⁻ + Cl₂ ⇒ 2Cl⁻
The half-reaction of reduction: chlorine is an electron acceptor, receives 1 electron, ie it is reduced
e.
Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂
3C⁺² ⇒ 3C⁺⁴ + 6e⁻
The half-reaction of oxidation: carbon is an electron donor, losses 2 electrons ie it is oxidized
6e⁻ + 2Fe⁺³ ⇒ 2Fe
The half-reaction of reduction: iron is an electron acceptor, receives 3 electrons, ie it is reduced
Answer: -
13.545
Explanation: -
Let the volume of the solution be 1000 mL
Density = 1.04 g/ mL
Mass = density x vol
= 1.04 g/ mL x 1000 mL
= 1040 g
Amount of NaOH = 
x 1040 g
= 14.04 g
Molar mass of NaOH = 23 x 1 + 16 x 1 + 1 x 1
= 40 g / mol
Number of moles = Amount of NaOH / Molar mass
= 14.04 /40
= 0.351 mol
So 1000 ml of the solution has 0.351 mol
Molarity of NaOH = 0.351 M
Using the relation
pOH = - log [OH-]
= - log 0.351
= 0.455
Using the relation pH + pOH = 14
pH = 14 - pOH
= 14 - 0.455
= 13.545
Answer:
i is the correct answer.
Explanation:
the RAM of aluminum is indeed 27. And since the RAM of substances are measured in terms of the C-12 isotope then R indeed explains why the RAM Al is 27.
