If the function is 
and f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.
Given function is and f(4) − f(1) = f '(c)(4 − 1).
In this question we have to apply the mean value theorem, which says that given a secant line between points A and B, there is at least a point C that belongs to the curve and the derivative of that curve exists.
We begin by calculating f(2) and f(5):
f(2)=
f(2)=1
f(5)=
f(5)=1
And the slope of the function:
(x)=
(c)=0
Now,
=-2
=0
-2 is not equal to 0. So there is not any answer.
Hence if the function is and f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.
Learn more about derivatives at brainly.com/question/23819325
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Answer:
7/13
Step-by-step explanation:
Let's call x= numerator
We know that :
Denominator= x+6
And
(numerator +2)/(denominator +2) = 3/5
So
(x+2)/(x+6+2)=3/5
(x+2)/(x+8)=3/5
(x+2)*5=(x+8)*3
5x+10=3x+24
2x=14
x=7
In the end
Numerator= x =7
Denominator=x+6 = 13
So the original number is 7/13
I hope this helps, have a beautiful day
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