Answer:
First, make the double negative a positive.
So, (-6/13) + (7/15)
Then multiply the numerator, 6×7=42
And denominator 13×15=195
42/195 simplify by dividing both by 3 so 14/65
Answer:
$1025
Step-by-step explanation:
We can use the 2-point form of the equation of a line to write a function that gives Justin's salary as a function of his sales.
We start with (sales, salary) = (400, 500) and (700, 575)
__
The 2-point form of the equation of a line is ...
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
salary = (575 -500)/(700 -400)(sales -400) +500
salary = 75/300(sales -400) +500
For sales of 2500, this will be ...
salary = (1/4)(2500 -400) +500 = (2100/4) +500 = 1025
Justin's salary after selling $2500 in merchandise is $1025.
Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Answer:
53/100
Step-by-step explanation:
First, we convert the fraction to a decimal number by dividing the numerator by the denominator:
8 / 15 = 0.533
There are two parts to the decimal number above:
Integer Part: 0
Fractional Part: 533
Now, we will make the Fractional Part just two digits (nearest hundredth) by using our rounding rules.*
In this case, Rule I applies, so 8/15 (or 0.533) rounded to the nearest hundredth in decimal format is:
0.53
Next, we will make 8/15 rounded to the nearest hundredth in fraction format. Since you can divide our decimal format answer above by 1 and keep the same value, you can make it like this:
0.53 = 0.53/1
Then, we multiply the numerator and denominator by 100 to get rid of the decimal point:
(0.53 x 100) / (1 x 100) = 53/100
That's it. 8/15 rounded to the nearest hundredth is displayed below (simplified if necessary):
53/100
We have to find the GCD between 10, 16 and 4 and between x^5, x^4 and x^2
GCD (10,16,4) = 2
GCD (x^5,x^4,x^2) = x^2
So we divide all terms for 2x^2
Final result: 2x^2(5x^3-8x^2+2)