The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.
<h3>What is the range of a quadratic equation?</h3>
In this case we have a <em>quadratic</em> equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.
x = - 9
y = (2 / 3) · (- 9)² - 6
y = 48
x = - 6
y = (2 / 3) · (- 6)² - 6
y = 18
x = - 3
y = (2 / 3) · (- 3)² - 6
y = 0
x = 0
y = (2 / 3) · 0² - 6
y = - 6
x = 3
y = (2 / 3) · 3² - 6
y = 0
x = 6
y = (2 / 3) · 6² - 6
y = 18
x = 9
y = (2 / 3) · 9² - 6
y = 48
The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.
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Answer:
or units.
Step-by-step explanation:
To find the <em>distance between two points</em>, we can use the Distance Formula.
Distance Formula:
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<u>Given:</u>
P (10, -7) ⇒ x₁ = 10, y₁ = -7
Q (7, -10) ⇒ x₂ = 7, y₂ = -10
Substitute the given values into the formula and simplify.
The distance between points P and Q is or units.
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Answer:
(1 + y)(x + 2y)
hope this is right
Step-by-step explanation:
We need 500 ml of alcohol mixture and 50 ml of water.
<u>Step-by-step explanation:</u>
The 50% concentration of the final solution is a result of mixing the 55% concentration with water, which is 0% concentration. Multiply the concentration of each liquid times the # of ml you will use, add these and divide by the total ml to get 50%
x = the number of ml of the 55% alcohol mixture
y = the number of ml of water
x + y = 550
Again, the 0 above represents the water which is 0% concentration
= 0.50
0.55 x = 275
x = = 500
plug 500 into the equation x + y = 550
500 + y = 550
y = 50
Use 500 ml of the 55% solution and 50 ml of water.
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http://www.wikihow.com/Solve-Pythagoras-Theorem-Questions