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Bad White [126]
2 years ago
9

Enter the answer to the problem below, using the correct number of

Mathematics
1 answer:
Lena [83]2 years ago
7 0

Answer:

‬80.796,64‬

Step-by-step explanation:

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Find the values of X and Y that makes these triangles congruent by the HL theorem
muminat

Answer:

C. x = 3, y = 2

Step-by-step explanation:

If both triangles are congruent by the HL Theorem, then their hypotenuse and a corresponding leg would be equal to each other.

Thus:

x + 3 = 3y (eqn. 1) => equal hypotenuse

Also,

x = y + 1 (eqn. 2) => equal legs

✔️Substitute x = y + 1 into eqn. 1 to find y.

x + 3 = 3y (eqn. 1)

(y + 1) + 3 = 3y

y + 1 + 3 = 3y

y + 4 = 3y

y + 4 - y = 3y - y

4 = 2y

Divide both sides by 2

4/2 = 2y/2

2 = y

y = 2

✔️ Substitute y = 2 into eqn. 2 to find x.

x = y + 1 (eqn. 2)

x = 2 + 1

x = 3

8 0
3 years ago
How do you round 1.038 to the nearest hundredth
Talja [164]
You have to go past the decimal point in since the first number in the tenths place is a zero you can't really round here so you go to the hundreds place and not so three you round down because 3 is closer to 0 then it is 10 so it would be 1. 4



3 0
3 years ago
Read 2 more answers
I hope this uploaded sorry still having a hard time with this one
Shkiper50 [21]
No problem 72 cubic squares
8 0
3 years ago
A parabola $ax^2+bx+c$ contains the points $(-1,0)$, $(0,5)$, and $(5,0)$. Find the value $100a+10b+c$.
victus00 [196]

Answer:

STOP CHEATING ON AOPS WORK!!!!

Step-by-step explanation:

1. pay attention in class

2. ask message board if you need to

3. stop googling answers

4. you paid lots of money for this course so its all going to waste now thanks to your laziness you ugly piece of sH*t

3 0
3 years ago
Find the perimeter of the quarter-circle. Give your answer to the nearest whole number.
Bezzdna [24]

Answer:

The perimeter of the quarter-circle is 200 cm.

Step-by-step explanation:

Given that the angle of quarter-circle is 90°. So using Length of Arc formula, you are able to find the length of curve :

arc =  \frac{θ}{360}  \times 2 \: \pi \: r

Let r be radius = 56 cm,

Let θ = 90°

arc =  \frac{90}{360}  \times 2 \times\pi \times 56

=  \frac{1}{4}  \times 2 \times \pi \times 56

=  \frac{1}{2}  \times \pi \times 56

= 28\pi \: cm

We have already found the arc. Next we have to add up together to find the perimeter :

p = 56 + 56 + 28\pi

p = 112 + 28\pi

p = 200 \: cm \: (3s.f)

6 0
2 years ago
Read 2 more answers
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