Since we don't have a figure we'll assume one of them is right and we're just being asked to check if they're the same number. I like writing polar coordinates with a P in front to remind me.

It's surely false if that's really a 3π/7; I'll guess that's a typo that's really 3π/4.

P(6√2, 7π/4) = ( 6√2 cos 7π/4, 6√2 sin 7π/4 )

P(-6√2, 3π/4) = ( -6√2 cos 3π/4, -6√2 sin 3π/4 )

That's true since when we add pi to an angle it negates both the sine and the cosine,

cos(7π/4) = cos(π + 3π/4) = -cos(3π/4)

sin(7π/4) = sin(π + 3π/4) = -sin(3π/4)

Answer: TRUE

3 0

3 years ago

(35 points) Hey please help quickly. :(

UkoKoshka [18]

Answer:here ya go boys

Step-by-step explanation:

6 0

3 years ago

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Simplify and express the result in power notation with positive exponent

Molodets [167]

Answer:

3²

Step-by-step explanation:

Given expression:

$\sf (3^{-3} \div 3^{-10}) \times 3^{-5}$

Following the <u>order of operations</u>, carry out the calculations inside the parentheses first.

$\textsf{Apply the quotient exponent rule} \quad a^b \div a^c=a^{b-c}:$

$\implies \sf 3^{-3-(-10)} \times 3^{-5}$

$\implies \sf 3^{-3+10} \times 3^{-5}$

$\implies \sf 3^{7} \times 3^{-5}$

$\textsf{Apply the product exponent rule} \quad a^b \times a^c=a^{b+c}:$

$\sf \implies 3^{7+(-5)}$

$\sf \implies 3^{7-5}$

$\sf \implies 3^2$

Learn more about exponent rules here:

brainly.com/question/27959936

brainly.com/question/24947526

4 0

2 years ago

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