3a^2 B^3 C^-2 OVER a^-3 b^6 c^3
Answer:
see explanation
Step-by-step explanation:
Using the Pythagorean identity
cos²A + sin²A = 1 ( divide terms by cos²A )
+
=
, that is
1 + tan²A = sec²A ← as required
Answer:
3/8
Step-by-step explanation:
3/4 divided by 2> 3/4 divided by 2/1>3*1=3 4*2=8 so therefore your answer is 3/8
Add it together. You find area with base times height!!!
Answer:
x = - 4 ± 2
Step-by-step explanation:
Given
f(x) = x² + 8x + 4
To find the zeros let f(x) = 0, that is
x² + 8x + 4 = 0 ( subtract 4 from both sides )
x² + 8x = - 4
To solve using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(4)x + 16 = - 4 + 16
(x + 4)² = 12 ( take the square root of both sides )
x + 4 = ±
= ± 2
( subtract 4 from both sides )
x = - 4 ± 2
Thus the zeros are
x = - 4 - 2
and x = - 4 + 2