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pishuonlain [190]
3 years ago
13

The sum of an even number and odd number is always even

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
7 0
Yes your correct but thats not a question
diamong [38]3 years ago
6 0
Even numbers are divisible by two and odd numbers are not.
Try some examples to see if you can find a counter-example.

2 + 3 = 5  (odd sum)

4 + 7 = 11 (odd sum)

20 + 9 = 29 (odd sum)

So the sum of an even number and odd number is odd, not even.  Your statement above is FALSE.
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Write 37/100 as a percentage.
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37%

Step-by-step explanation:

37% equal 37 of a whole 100 is a whole

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Furkat [3]

Answer:

17.80% probability that all of them are wearing their seat belts.

Step-by-step explanation:

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not. The drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers. So we use the normal probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Police estimate that​ 25% of drivers drive without their seat belts.

This means that 75% wear their seatbelts, so p = 0.75

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This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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17.80% probability that all of them are wearing their seat belts.

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3 years ago
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