All categories

3 years ago

I dont know how to get people to answer but please i really really need help fast im begging anyone

Mathematics

2 answers:

sesenic [268]3 years ago

7 0

The one above is right!

AnnyKZ [126]3 years ago

6 0

Answer:

75 + m ≥ 495

m ≥ 420

Step-by-step explanation:

You might be interested in

Hiii how are you guys doing if you answer this I’ll give you points and make you brainly or what ever it’s called and how do you

baherus [9]

Answer:

Hi how is your day going?

Step-by-step explanation:

I have some jokes and I hope you like them.

Knock Knock.

Who's There?

Scold.

Scold who?

Scold outside, let me in!

Knock Knock.

Who's there?

Tank.

Tank who?

You're Welcome!

7 0

3 years ago

Write the ratio 48:30:42 in its simplest form

Zielflug [23.3K]

Answer- 8:5:7

Explanation:
Find the greatest common factor for all of them. Which is 6.
Then you just divide each number by 6
48/6= 8
30/6= 5
42/6= 7
Making it 8:5:7

7 0

3 years ago

PLEASE HELP!! What is the value of y in the product of powers below?

Eduardwww [97]

4 will be y hope this helps u

6 0

3 years ago

Read 2 more answers

Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw

PolarNik [594]

Answer:

Using backward reasoning we want to show that "We can never get nine 0's".

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

There were 9 0's:

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

There were 9 1's:

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

5 0

3 years ago

The diameter of cold virus cell is about 3x10-9 meter,and the diameter of a streptoccus bacterium cell is about 9x10-7 meter. Wh

Archy [21]

Here we need to compare the orders of magnitude of two measures.

We will see that the bacteria is 300 times larger than the virus.

We know that:

The diameter of the virus-cell is:

$D_v = 3 \cdot 10^{-9} m$

The diameter of the bacteria cell is:

$D_b = 9 \cdot 10^{-7} m$

So, to compare them, first notice that both are in the same units, meters, so we only need to compare the numbers.

Is common sense to identify the one with the largest exponent as the largest number, and the largest exponent is -7, thus the bacteria should be the larger one.

But let's prove this with math, remember the property:

$\frac{a^n}{a^m} = a^{n - m}$

Let's take the quotient between the diameters and see what we get, I will use the diameter of the bacteria in the numerator, thus if the quotient is larger than 1, it would mean that the bacteria is greater and by how much.

$quotient = \frac{ 9 \cdot 10^{-7} m}{ 3 \cdot 10^{-9} m} = \frac{9}{3} \cdot 10^{-7 + 9}\\\\= 3*10^2$

So we can say that the bacteria is 3*10^2 = 3*100 = 300 times larger than the virus.

If you want to learn more, you can read:

brainly.com/question/4953281

8 0

2 years ago