Question

The time-average power carried by a UPEMW propagating in vacuum is 0.05 W/m2. i) What is the amplitude value of the electric field and the amplitude value of the magnetic field in the wave

Answer 1

Answer:

The correct solution is "11.51 mA".

Explanation:

Given:

Time average power,

$P_{avg}=0.05 \ W/m^2$

n = 377

As we now,

⇒ $P_{avg}=\frac{E_0^2}{n}$

or,

⇒ $E_0^2=0.05\times 377$

⇒       $=4.341 \ V$

hence,

⇒ $H_0=\frac{E_0}{n}$

By putting the values, we get

         $=\frac{4.341}{377}$

         $=11.51 \ mA$