Answer:
The answer to the question is
The ball will go 0.14 meters high if the gun is aimed vertically
Explanation:
The energy in the spring → Energy, E =
Where E = energy in the spring
k = Spring constant
x = Spring compression or stretch
Therefore E =
The spring energy is transferred to the ball as kinetic energy based on the first law of thermodynamics which states that energy is neither created nor destroyed
Kinetic energy = KE =
From which v = = = 1.66 m/s
from v² =u² - 2·a·S
Where v = final velocity = 0 m/s
u = initial velocity = 1.66 m/s
a = g = Acceleration due to gravity
S = height
Therefore 0 = 1.66² - 2×9.81×S
or S = 1.66² ÷ (2×9.81) = 0.14 m
Hey there!
Based on the info this planet is likely to be located near the sun. If you would like to be exact it would be between Mercury and Venus. This is because it’s orbital period is half a year, Venus is about 3/4 of a year, and Mercury is about 1/3 of a year. Hopefully this helps! Good luck!
Well the centripetal acceleration would be 9.82 squared. That is the correct answer. I hope this helped you. Have a great day! :)
Wavelength and frequency have a reciprocal relationship. If one doubles, the other halves.
The mean may be calculated by summing the values of the refractive index and dividing the sum by the number of experiments. This is:
Mean = (1.45 + 1.56 + 1.54 + 1.44 + 1.54 + 1.53)/6
Mean = 1.51
The mean absolute error is the sum of the absolute values of errors divided by the number of trials:
MAE = (|1.45-1.51|+|1.56-1.51|+|1.54-1.51|+|1.44-1.51|+|1.54-1.51|+|1.53-1.51|)/6
MAE = 0.043
The fractional error is the MAE divided by the actual value:
Fractional error = 0.043 / 1.51
Fractional error = 43/1510
The percentage error is the fractional error multiplied by 100:
Percentage error = 2.85%