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3 years ago

6

Amy, Dan, and mike are competing in a cooking competition. They all used different amounts of milk from a container holding 6 ga

llons of milk. Amy used 13

1 answer:

Flauer [41]3 years ago

4 0

Answer:

2 1/6 containers of milk, if that's what you're asking.

Step-by-step explanation:

You might be interested in

A bakery used 38 pounds of flour to make French bread and

fomenos

Answer:

since we are not given the options, I will write down a few equations that represent the number of French bread loaves and bagels:

a = number of loaves of French bread
b = number of bagels
available amount of flour = 38

2a + b ≤ 38

2a ≤ 38 - b

a ≤ (38 - b) / 2

a ≤ 19 - 0.5b

b ≤ 38 - 2a

b ≤ 2(19 - a)

Hopefully one of these equations is one of the choices given to you.

8 0

3 years ago

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

KiRa [710]

Answer:

1863 $meters^{2}$

Step-by-step explanation:

( 23 x 12 ) x 2 = 552

69 x 19 = 1311

1311

<u>+552</u>

= 1863 $meters^{2}$

8 0

3 years ago

Hi i need you to convert 9/15 into a decimal and show work please!

kozerog [31]

Answer:

0.6

Step-by-step explanation:

9 is the numerator and 15 is the denominator

divide 9 ÷ 15

which is 0.6

3 0

2 years ago

Read 2 more answers

A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of

Gwar [14]

$\bold{\huge{\underline{ Solution}}}$

<h3><u>Given </u><u>:</u><u>-</u></h3>

A marker in the center of the fairway is 150 yards away from the centre of the green
While standing on the marker and facing the green, the golfer turns 100° towards his ball
Then he peces off 30 yards to his ball

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>

<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>

Let assume that the distance between the golf ball and central of green is x

<u>Here</u><u>, </u>

Distance between marker and centre of green is 150 yards
<u>That </u><u>is</u><u>, </u>Height = 150 yards
For facing the green , The golfer turns 100° towards his ball
<u>That </u><u>is</u><u>, </u>Angle = 100°
The golfer peces off 30 yards to his ball
<u>That </u><u>is</u><u>, </u>Base = 30 yards

<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

$\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}$

Here, a = perpendicular height
b = base
c = hypotenuse
cos theta = Angle of cosine

<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

$\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}$

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}$

$\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}$

$\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}$

$\sf{ x^{2} = 22500 + 900 + 156.6}$

$\sf{ x^{2} = 23556.6}$

$\bold{ x = 153.48\: yards }$

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0

2 years ago

There are two less nickels than dimes, and as many quarters, as nickels and dimes together. The total amount of money is $5.25.

katen-ka-za [31]

N=d-2
q=n+d =>q=(d-2)=q=2d-2
25q+5n+10d=525
replace q and n with d
25(2d-2) +5(d-2)+10d=525
50d-50+5d-10+10d=525
65d=585
d=9
n=7
q=16

3 0

3 years ago