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Salsk061 [2.6K]
4 years ago
5

Which points define the solution set of this linear-quadratic system of equations?

Mathematics
2 answers:
mezya [45]4 years ago
7 0
The answer is a.
Point A and point B
Sauron [17]4 years ago
6 0

Answer:

what he said

Step-by-step explanation:

rate

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Find the equation of the line parallel to the given line and passing through the given point x=4; (6,2)
emmasim [6.3K]

Therefore the equation of the line is

     x= 6

Step-by-step explanation:

Given, equation of line is  x = 4

The equation of line which is parallel to the above line is

x= a .........(1)

Since the line passes through the point (6,2) . Then the point will be satisfy the equation of line .

∴6 = a    [ putting x =6  and y = 2 in equation  (1)]

Therefore the equation of the line is

     x= 6

4 0
4 years ago
A house is on a 60,000-squarefoot lot. rounded to the nearest tenth, approximately how many acres are in the lot? note: there ar
bagirrra123 [75]

The computation shows that the acres that are in the lot will be 1.38 acres.

<h3>How to compute the value?</h3>

It should be noted that the information is that the house is on a 60,000-squarefoot and the there are 43,560 square feet in an acre.

Therefore, the acres in the lot will be:

= 60000/43560

= 1.38 acres

Therefore, the computation shows that the acres that are in the lot will be 1.38 acres.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

8 0
1 year ago
Point A is located at (0, 4) and point B is located at (−2, −3). Find the x value for the point that is 1 over 4 the distance fr
Vesna [10]

Answer: -0.5

<u>Step-by-step explanation:</u>

the x-value for A is 0.  

the x-value for B is -2.  

The total distance from A to B is -2.

\frac{1}{4}(-2) = -0.5

  A + -0.5

= 0 - 0.5

=  -0.5

7 0
3 years ago
Read 2 more answers
A third-grade class is told to send a valentine to every single one of their classmates. On Valentine’s Day, the class ends up w
FinnZ [79.3K]
306 is the total cards sent by all the students in the class. Lets say x is the number of students in class, therefore each student needs to send x-1 cards (since they do not send themselves a card). So depending on your level of math, you could either take the complex way to solve it using quadratic equations, or just find the number that if multiplied by itself then subtracted, gives you 306.
(x \times x) - x = 306 \\ lets \: try \: 18 \\ (18 \times 18) - 18 = 306 \\ so \: x = 18
===============
Complex way
(x \times x) - x = 306 \\ {x}^{2} - x - 306 = 0
So a = 1, b = -1, c=-306
using the quadratic equation:
x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a}
x = \frac{1 + \sqrt{1 - (4 \times 1 \times - 306)} }{2} \\ x = \frac{1 + \sqrt{1 - ( - 1224)} }{2} \\ x = \frac{1 + \sqrt{1225} }{2} \\ x = \frac{1 + 35}{2} \\ x = \frac{36}{2} \\ x = 18
8 0
3 years ago
Read 2 more answers
Show that the expression (x+y)(x-y)-14x+49 may be written as the difference of two squares.
iren [92.7K]
For
(a-b)(a+b)=a^2-b^2

x^2-y^2-14x+49
x^2-14x+49-y^2
(x-7)^2-y^2
(x-7-y)(x-7+y)
or
(x-y-7)(x+y-7)
8 0
4 years ago
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