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3 years ago

Use the drop-down menus to locate integers on the number line.

Mathematics

2 answers:

ahrayia [7]3 years ago

7 0

A is -4

B is -1

C is +2

D is +6

( example: +3 is positive 3

-3 is negative 3 )

Hope this helped!

harkovskaia [24]3 years ago

7 0

Answer:

✔ -4

✔ -1

✔ 2

✔ 6

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N aquarium tank holds

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1 gal = 3.8 liters....so 65 gallons = 65 * 3.8 = 247 liters

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3 years ago

Help help help help help Select the equivalent expression (3^2x5^3

swat32

Answer:

Step-by-step explanation:

(3^2x5)^3=91125

3^6x5^3=91125

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2 years ago

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PLZ HELP ME!!!! I NEED THE ANSWER QUICK SO IM GIVING BRAINLIEST TO THE FASTEST AND BEST ANSWER.

geniusboy [140]

Answer:

f(x) = 8(1/2)^x.

Step-by-step explanation:

According to the graph, there is a point at (0, 8) and (1, 4).

That means that when x = 0, y = 8.

8 = a(b)^0

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a = 8

That means that a = 8, and when x = 1, y = 4.

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4 = 8b

8b = 4

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b = 1/2

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Hope this helps!

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3 years ago

Which of the four triangles below are similar?

KiRa [710]

The answer is B

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2 years ago

Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the

sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let $y(t)$ be the depth of water in the barrel at time $t$ , where $y$ is measured in inches and $t$ in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

$\frac{dy}{dt}=-k\sqrt{y}$

where $k$ is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by $\frac{1}{\sqrt{y}}$

$\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k$

Multiply by $dt$

$\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt$

Take integral

$\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt$

Integrate

$2\sqrt{y}=-kt+C$

Isolate $y$

$y(t)=(\frac{C}{2} -\frac{k}{2}t)^2$

We know that the water level starts at 36, this means $y(0)=36$ . We use this information to find the value of $C$ .

$36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12$

$y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2$

At t = 1, y = 34

$34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}$

So our formula for the depth of water in the barrel is

$y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\$

To find the time, $t$ , at which all the water leaks out of the barrel, we solve the equation

$\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49$

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0

3 years ago