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3 years ago

(X-5)(x+15)=52 find x

Mathematics

1 answer:

Ghella [55]3 years ago

4 0

Answer:

x=-5+2 $\sqrt{38}$ ,-5-2 $\sqrt{38}$

Step-by-step explanation:

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Well there eqaul but one is just got the internet added to there home

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3 years ago

Can you help me by showing work on some of them please I’m having trouble

Xelga [282]

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3 years ago

PLEASE HELP!!<br> Name the solution to this system of equations:

RoseWind [281]

9514 1404 393

Answer:

(x, y) = (3, -1)

Step-by-step explanation:

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3 years ago

Middletown sponsors a two day conference for selected middle school students to study government. Suppose 20 student delegates w

grandymaker [24]

Answer:

North Middle School = 10 students
Central Middle School = 6 students
South Middle School = 4 students

Step-by-step explanation:

First calculate the total number of students in all the schools:

= 618 + 378 + 204

= 1,200 students

Use this number to calculate the proportion of the total population that a school so that this can then be used to determine the proportion of the 20 delegates they should sent.

North Middle school:

= 618/1,200 * 20

= 10 students

Central Middle School:

= 378 / 1,200 * 20

= 6 students

South Middle School:

= 204/1,200 * 20

= 4 students

5 0

2 years ago

assume that the number of production defects is 28 and that 14 of these are classified as major defects, 8 are classified as des

Arlecino [84]

Answer: 5

Step-by-step explanation:

Let A denotes the number of major defects and B denotes the number of design defect.

By considering the given information, we have

$U=28\ ;\ n(A)=14\ ;\ n(B)=8\ \ ;\ n(A^c\cap B^c)=1$

Now, the number of major defects or design defects:

$n(A\cup B)=U-n(A^c\cap B^c)=28-11=17$

Also,

$n(A\cap B)=n(A)+n(B)-n(A\cup B)\\\\\Rightarrow\ n(A\cap B)=14+8-17=5$

Hence, the number of design defects were major=5

6 0

3 years ago