Answer:
11 meters
Step-by-step explanation:
In 1852 its height was 29.002ft or 8.839m, while the measuring in 1999 said that it was 29.035ft or 8.850m. That means that it is taller by some 11 meters or 33 feet. That is because it keeps increasing its size since its positioned on such plates that hit each other.
(<span>4/9)/x = 12 </span>
<span>12x = 4/9 </span>
<span>x = 4 / (9•12) = 1 / (9*3) = 1/27</span>
Answer:
yes, if AB ≅ DE
Step-by-step explanation:
Triangles are said to be congruent if they have the same sides and the same angles.
The following measures are used to determine if triangles are congruent:
1) Angle-side-angle: If two angles and a side of a triangle is equal to two angles and corresponding side of another triangle, then they are congruent.
2) Side-side-side: If all three sides of a triangle is equal to three sides of another triangle, then the two triangles are congruent.
3) Side angle side: If two sides and an included angle of a triangle is equal to the two sides and corresponding angle of another triangle, then they are congruent.
4) Hypotenuse - leg: If the hypotenuse and one leg of a triangle is equal to the hypotenuse and leg of another triangle then they are congruent.
From the triangles DEF and ABC, already, they already have one equal triangle that is ∠F = ∠B and an equal side i.e DF = AC.
To satisfy congruence, two sides and an angle have to be equal, therefore if AB = DE then the two triangles would be congruent
Answer:
3(t+2)
Step-by-step explanation:
As with any problem involving division of fractions, you can invert the denominator and multiply.
Your knowledge of the factoring of the difference of squares helps. If that doesn't work for you, you can always use synthetic division or polynomial long division to find the quotient of (t^2-4) and (t-2).
The correct answer is B. I figured this out by testing out coordinates into each equation. I am only going to show my work for equation B though... if you want to see the rest of my work, message me.
(0,0) ⇒ this point is within the shaded part of the graph
0 ≤ 1/2(0) + 3
0 ≤ 0 + 3
0 ≤ 3
True
(1,4) ⇒ this point is within the unshaded region
4 ≤ 1/2(1) + 3
4 ≤ 1/2 + 3
4 ≤ 3.5
False
This proves that equation B matches the graph shown.
