Answer:
The forces of attraction are weak in gases.
Explanation:
Solid-state objects are presented as bodies in a definite form; their atoms are often intertwined into narrowly defined structures, which gives them the ability to withstand forces without apparent deformation. They are generally described as hard as well as resistant, and in them, the forces of attraction are greater than those of repulsion. In the crystalline solids, the presence of small intermolecular spaces gives way to the intervention of the bond forces, which place the cells in geometric forms.
Solid – In a solid, the attractive forces keep the particles together tightly enough so that the particles do not move past each other. Their vibration is related to their kinetic energy. In the solid the particles vibrate in place.
Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container. The attractive forces between particles are strong enough to hold a specific volume but not strong enough to keep the molecules sliding over each other.
Gas – In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other. In most cases, there are essentially no attractive forces between particles. This means that a gas has nothing to hold a specific shape or volume.
Answer: 
Explanation:
Given
Car drives 215 km east and then 45 km North
Displacement is East direction is
Now, the displacement from that to 45 km North is given by
Net displacement is 
Magnitude of the displacement is
Whether a line is "steep" or "shallow" depends on the slope of the line. In the equation y=mx+b, m is the slope. In your first equation, 1/2x+4, the slope would be 1/2 which means there is 1 increase in the vertical, or y, value for each 2 increases in the horizontal, or x value. This line would be shallow.
Answer:
32.5 ms⁻¹
Explanation:
<em><u>Theory
</u></em>
<u>
The law of conservation of linear momentum
</u>
The sum of linear momentum of a system under no external force remains constant.
In this scenario although different forces act on two vehicles by each other when we consider the total system of two cars no external unbalance force act on them. So we can apply this law.
As law says,
The sum of linear momentum before collision = The sum of linear momentum after collision.
Momentum = mass × velocity
1000×40+3000×35 = 1000×v + 3000×37.5
where v = velocity of the red car after the cash
v = 32.5 ms⁻¹
