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Nonamiya [84]
3 years ago
11

The decibel scale is used to measure the perceived loudness of a sound. a. True b. False

Physics
1 answer:
Mademuasel [1]3 years ago
8 0
True because when you look at the scale you see that some louder things are higher on it than others
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What does it mean to have an acceleration of -10 m/s^2 when the velocity is 80 m/s?
mamaluj [8]

Answer:

1,3

Explanation:

As the acceleration is -10m/s^2 , that means deceleration is occurring. That means, the object is slowing down.

v=u-at

or, 0=80-10t

or, t=8 seconds

So, the object will stop in 8 seconds.

So, the correct answers are 1 and 3.

Hope, this helps you.

3 0
3 years ago
Suppose an element had an atomic number of 52. How many protons would that element have?
frutty [35]
The element would have 52 protons because atomic number gives protons.
4 0
2 years ago
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Find the mass of a flying discus that has a net force of 1.05 newtons and accelerates at 3.5 m/s^2
Ilya [14]
F=ma
m=1.05/3.5= 0.3kg
8 0
3 years ago
Having landed on a newly discovered planet, an astronaut sets up a simple pendulum of length 1.38 m and finds that it makes 441
Tasya [4]
The period of a simple pendulum is given by:
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the pendulum length, and g is the gravitational acceleration of the planet. Re-arranging the formula, we get:
g= \frac{4 \pi^2}{T^2}L (1)

We already know the length of the pendulum, L=1.38 m, however we need to find its period of oscillation.

We know it makes N=441 oscillations in t=1090 s, therefore its frequency is
f= \frac{N}{t}= \frac{441}{1090 s}=0.40 Hz
And its period is the reciprocal of its frequency:
T= \frac{1}{f}= \frac{1}{0.40 Hz}=2.47 s

So now we can use eq.(1) to find the gravitational acceleration of the planet:
g= \frac{4 \pi^2}{T^2}L =  \frac{4 \pi^2}{(2.47 s)^2} (1.38 m) =8.92 m/s^2
3 0
3 years ago
For life to flourish on Earth, several changes occurred that affected the atmosphere, such as _____.
e-lub [12.9K]
Evolution of cyanobacteria that produce O2volcanic outgassing to create a thicker atmosphereformation of an ozone layer to block harmful radiationall of the above<span>only a and c

Are the options</span>
8 0
2 years ago
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