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Rus_ich [418]
3 years ago
9

In a triangle the measure of the first angle is twice the measure of the second angle. the measure of the third angle is 8 degre

e less than the measure of second angle what is the measure of each angle
Mathematics
1 answer:
Rufina [12.5K]3 years ago
4 0
Let's call the missing angles Q, R, and S. We know that Q = 2R and S = R - 8 and we also know that Q + R + S = 180. So that really just means that              180 = 4R - 8  Add 8 on both sides of the equal sign
188 = 4R So we divide on both sides of the equal sign by 4
47 = R And that means that Q = 2 * 47 So Q = 94 and S = 47 - 8 So S = 39
39 + 94 + 47 = 180
The missing angles are 39 degrees 94 degrees and 47 degrees.

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What is the equation of the line that is parallel to the line y =1/3 x + 4 and passes through the point (6, 5)?
lianna [129]

Answer:

y = \frac{1}{3} x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{1}{3} x + 4 ← is in slope- intercept form

with slope m = \frac{1}{3}

Parallel lines have equal slopes , then

y = \frac{1}{3} x + c ← is the partial equation

To find c substitute (6, 5) into the partial equation

5 = 2 + c ⇒ c = 5 - 2 = 3

y = \frac{1}{3} x + 3 ← equation of parallel line

5 0
3 years ago
What is the value of x ?
jeyben [28]
X is going to equal 2.75
3 0
3 years ago
Read 2 more answers
Please help on this math problem pls
Arlecino [84]

Answer:

8

Step-by-step explanation:

To find the mean, you add up all the numbers and divide it by the total number of numbers. So 4+5+7+8+11+13 is 48. There are 6 numbers. So 48/6=8.

5 0
3 years ago
Read 2 more answers
A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

8 0
3 years ago
I can't solve it, so, here goes nothin'. "Some people are on a train, 19 people get off at one stop, then, the next one 13. Now
Stolb23 [73]

19+13=32

32+63=95

95-4=91

91+10=101

This means that 101 people are now on the bus.

HOPE THIS HELPS <3

4 0
2 years ago
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