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3 years ago

5

The library is halfway between your house and your school. If your house is located at (-4,-3) and the library is at (2,-1), wha

t are the coordinates of your school?

1 answer:

aleksandrvk [35]3 years ago

6 0

I believe it would be (-2,-2) i may be wrong though i dont have my graphing papers

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a winery has a vat with two pipes leading to it. the inlet pipe can fill the vat 7 hours, while the outlet pipe can empty it in

raketka [301]

Lets say, for ease, that the vat can hold a total of 70 gallons (or whatever you would like to use.) Use whatever number you want, I just picked this because it gives us a lot of clean numbers.

Now, if the inlet can fill it in 7 hours, that means that it is adding 10 gallons per hour. (70 gal/7 hours = 10 gal/hr)

For the outlet, use the same process, and you find that it drains the vat at 7 gallons per hour.

So, if you subtract the outlet from the inlet, you get 10 - 7 = 3 gallons per hour added.

Now just divide the size of the vat by that number, and you find your answer.

70 gallons / 3 gallons per hour = 23 1/3 hours.

6 0

2 years ago

II. Let f(x) = 9 – x , g(x) = x2<br> + 4, and h(x) = x – 2. Compute the following:<br> 7. g(f(12))

Alex17521 [72]

G(f(12))
f(12) = 9 - 12 = -3
g(-3) = (-3)^2 + 4 = 9 + 4 = 13

4 0

2 years ago

What is the value of x?<br> 40<br> 550<br> A. 1059<br> B. 75°<br> C. 850<br> D. 95°

antoniya [11.8K]

Answer:

the answer is 85° because all angles in a triangle add up to 180

so u add them both up, subtract from 180 n u get 85

6 0

2 years ago

Read 2 more answers

The shortest living domestic cat measure 133.4 milimeters tall is the cat?

Vikki [24]

Answer:

Its 133.4 millimeters?

Step-by-step explanation:

7 0

2 years ago

(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX

pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

$P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z$

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

$P(4$

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

$P(X$

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

$P(X$

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

$P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z$

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0

2 years ago