Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
Answer:
Step-by-step explanation:
36 d²-36 d+9=9(4d²+4d+1)
=9[4d²+2d+2d+1]
=9[2d(2d+1)+1(2d+1)]
=9(2d+1)(2d+1)
=9(2d+1)²
=[3(2d+1)]²
=(6d+6)²
length=6d+6
perimeter=4(6d+6)=24d+24
when d=2
length=6×2+6=18in
perimeter=4×18=72 in
area=18²=324 in²
(193/400 )x100 equals 48.25 %
Answer:
X<-2
Step-by-step explanation:
