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Lera25 [3.4K]
4 years ago
13

What are the right answers and how do you find it?

Mathematics
1 answer:
IceJOKER [234]4 years ago
8 0
This is the correct answers

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Natasha_Volkova [10]

Answer:

I'm pretty positive its (0, 0)

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3 years ago
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Please please please help!!!
jonny [76]

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8 0
3 years ago
Please help, I'd greatly appreciate it ​
NeX [460]
<h2>♥Bonjour dear♥</h2>

Your answer is=>

{ \bold{ =  > y - 3 =  \frac{1}{2} (x + 6)}}

{ \bold{ =  > y - 3 =  \frac{1x}{2}  +  \frac{6}{2} }}

{ \bold{ =  > y - 3 =  \frac{1x}{2}  + 3 }}

{ \bold{ =  > y  =  \frac{1x}{2}  + 3 + 3}}

{ \bold{ =  > y =  \frac{1x}{2}  + 6 }}

✌Do mark my answer as brainliest ✌ ♥And follow me♥

8 0
3 years ago
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Given the data below, which set of numbers contains the lower quartile, median, and upper quartile?
devlian [24]
Put the data in order from least to greatest.....

24, 27, 28, 28, 29, 31, 32, 36, 38
          ^             ^              ^
      27.5(Q1)   29(Q2)     34(Q3)

The answer choice that you chose must have 27.5, 29, and 34 in it. Which would be the third choice, {27.5, 29, 34}

Hope this helps! :D


6 0
4 years ago
Solve each problem by using the quadratic formula. Write solutions in simplest radical form. 2x2 – 2x – 1 = 0
monitta
When you have a quadratic in the form ax² + bx + c = 0, you can solve for x using the quadratic formula, which is as follows:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
In this case, a = 2, b = -2, and c = -1. Let's plug these in.
x=\frac{-(-2)\pm\sqrt{(-2)^2-4(2)(-1)}{2(2)}
Simplify...
x=\frac{2\pmsqrt{4+8}}4

x=\frac{2\pmsqrt{12}}4

\sqrt{12}=\sqrt{2\times2\times3}=2\sqrt{3}

x=\frac{2\pm2\sqrt{3}}4

x=\frac{1\pm\sqrt{3}}2

\boxed{x=\frac{1+\sqrt{3}}2\ or\ \frac{1-\sqrt{3}}2}
8 0
3 years ago
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