Question

I need help with angles in a triangle to find x I need help with these. please :(

Answer 1

Answer:

$a. \: \: x = {60}^{o}$

$b. \: \: x = {24}^{o}$

Step-by-step explanation:

Hint :

Sum of angles = 180°

Simplify :

$a. \: \: {x}^{o} + {40}^{o} + {80}^{o} = {180}^{o}$

${x}^{o} + {120}^{o} = {180}^{o}$

${x}^{o} = {180}^{o} - {120}^{o}$

${x}^{o} = {60}^{o}$

$b. \: 96+(x+12)+2x=180$

$x+108+2x=180$

$3x+108=180$

$3x=180−108$

$3x=72$

$x = \frac{72}{3}$

$x = 24$

Hope it is helpful...