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Vlad [161]
2 years ago
7

PLEASE HELP QUICK!! I NEED IT ASAP 6.

Mathematics
2 answers:
SOVA2 [1]2 years ago
8 0
The answer you’re looking for is C
sukhopar [10]2 years ago
4 0

Answer:

the answer C

Step-by-step explanation:

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Which statement must be true about the diagram?
sertanlavr [38]

Ray KM is an angle bisector of NKL.

8 0
3 years ago
Read 2 more answers
What product have the same sign as ( -2 3/7 ) (-6/11) ?
motikmotik

Answer:

1. -7/8

2.-9/14

3. 9/14

4. 7/8

2. what is the product of -2/7 and -3/7?

1. -7/8

2.-6/49

3. 6/49

4. 7/8

How do the expressions 72÷ 9 and -72÷ (-9) compare when they are evaluated?

1. They have different values and are different signs.

2. They have different values but are the same sign.

3. They have the same value but are different signs.

4. They have the same value and the same sign.

Step-by-step explanation:

Multiplying fractions: multiply numerators and multiply denominators

1. 3/4 X -6/7 = -18/28 = -9/14

2. -2/7 X -3/7 = 6/49

3. 4 because 72/9 is 8.  -72/-9 is 8.  Two negatives makes a positive when multiplying and dividing.

7 0
3 years ago
F(n) = f(n – 1) + f(n – 2); f(1) = 2; f(2) = 1.
Alex Ar [27]

f(n) is the nth term

Each term f(n) is found by adding the terms just prior to the nth term. Those two terms added are f(n-1) and f(n-2)

The term just before nth term is f(n-1)

The term just before the (n-1)st term is f(n-2)

----------------

For example, let's say n = 3 indicating the 3rd term

n-1 = 3-1 = 2

n-2 = 3-2 = 1

So f(n) = f(n-1) + f(n-2) turns into f(3) = f(2) + f(1). We find the third term by adding the two terms just before it.

f3) = third term

f(2) = second term

f(1) = first term

8 0
2 years ago
What is the position of A on the number line below?
Umnica [9.8K]

Answer:

so a fraction itll be a 4/5

7 0
2 years ago
Consider a population of Pacific tree frogs (Pseudacris regilla). In this population of frogs, a single locus controls the produ
zloy xaker [14]

Answer:

Step-by-step explanation:

Hello!

Use these data to calculate the chi-square statistic. Report your calculated chi-square statistic to two decimal places.

In this example, the study variable is X: genotype of a single locus two allele gene that codes the mating call of tree frogs. Categorized: S₁S₁, S₁S₂, and S₂S₂.

Usually, when you have a sample of observed genotypes of a gene of interest, the goal is to check if these genotypes follow a theoretical model such as the frequency models proposed by Mendel.

In Mendelian genetics, when two heterozygous individuals (Aa, Aa) from the F1 generation are crossed, you expect the next generation (F2) to show the genotypic ratio 1:2:1 ⇒ This model means that out of 4 descendants 1 will have the genotype AA, 2 will have the genotype Aa and 1 will have the genotype aa. Since there is no theoretical model specified I'll use the mendelian ratio 1:2:1.

If this theory applies to the population then we'll expect that the proportion of the first genotype is P(S₁S₁)= 0.25, the second P(S₁S₂)= 0.5 and the third P(S₂S₂)=0.25

To test if the observed genotypes follow the theoretical model you have to apply a Chi-Square Goodness of Fit Test.

For this test the hypotheses are:

H₀:P(S₁S₁)= 0.25; P(S₁S₂)= 0.5; P(S₂S₂)=0.25

H₁: The data is not consistent with the specified distribution.

α: 0.05

Statistic: X^2= sum(\frac{(o_i-e_i)^2}{e_i} )~X^2_{k-1}

Where:

oi: Observed frequency for the i- category

ei: Expected frequency for the i-category

k= number of categories

The rejection region for this test is one-tailed to the right. This is so because if the observed and expected values are too different (the chi-square value will be high) this will mean that the population doesn't follow the theoretical model and thus reject the null hypothesis. If the differences between what's observed and what's expected are small, this will mean that the population follows the theoretical model (and you'll obtain a small chi-square value) and you will not reject the null hypothesis.

The critical value is:

X^2_{k-1; 1 - \alpha }= X^2_{3;0.95}= 7.815

If the statistic is at least 7.815, the decision is to reject the null hypothesis.

If the statistic is less than 7.815, the decision is to not reject the null hypothesis.

Step 1 is to obtain the expected frequencies for each category:

e_i= n*P_i

e_{S_1S_1}= n * P(S_1S_1)= 1341*0.25= 335.25

e_{S_1S_2}= n * P(S_1S_2)= 1341 * 0.5= 670.5

e_{S_2S_2}= n * P(S_2S_2)= 1341*0.25= 335.25

Note: the summatory of the expected frequencies is equal to the total of observations ∑ei= n. If you have doubts about your calculations, you can add them to check it: ∑ei= 335.25 + 670.5 + 335.25= 1341

X^2= (\frac{(987-335.25)^2}{335.25} )+(\frac{(333-670.5)^2}{670.5} )+(\frac{(21-335.25)^2}{335.25} ) = 1731.50

Decision: Reject null hypothesis.

I hope this helps!

3 0
3 years ago
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