Find the 76th term on the arithmetic sequence 4, 7, 10, 13

Mathematics

1 answer:

sveta [45]3 years ago

7 0

Answer:

229

Step-by-step explanation:

1) the difference of the sequence is:

d=7-4=10-7=13-10=3.

2) the common view of the formula of the n term is:

a(n)=a(1)+d*(n-1), where n - required number of the term (it is 76), d- the calculated difference, a(1) - the 1st term of the given sequence.

3) according to the formula above it is possible to substitute n=76, d=3 and 4, then:

a(76)=4+3*(76-1)=4+225=229.

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