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Irina18 [472]
3 years ago
6

I WILL GIVE BRAINLIEST And more points please answer

Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0

Answer: Linda's 1/2 .  Phil's $0.50

Step-by-step explanation: the rate is the slop which is rise/run if that makes sense

grigory [225]3 years ago
3 0

Answer:

Step-by-step explanation:

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Which of the following describes the graph y=[x-2]?
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A furnace operates at 2,300°F.
Cloud [144]

Answer:

T = 2,300 + q × 250

6 0
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Write an equation of a parabola in vertex form. Vertex (2,-3) and passes through (0,5)​
nydimaria [60]

Answer:

Step-by-step explanation:

The vertex form of a parabola is given by  y = a(x - h)^2 + k, where (h, k) is the vertex.

Given vertex at (2,-3), h = 2, k = -3

y = a(x - 2)^2 + (-3) = a(x - 2)^2 - 3

The parabola passes through (0,5) so

5 = a(0 - 2)^2 - 3

5 = 4a - 3

4a = 8

a = 2

The parabola equation in vertex form:

y = 2(x - 2)^2 - 3

3 0
3 years ago
If Tanisha has ​$1000 to invest at 7​% per annum compounded semiannually​, how long will it be before she has ​$1600​? If the co
Sphinxa [80]

Answer:

Using continuous interest 6.83 years before she has ​$1600​.

Using continuous compounding, 6.71 years.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit year and t is the time in years for which the money is invested or borrowed.

Continuous compounding:

The amount of money earned after t years in continuous interest is given by:

P(t) = P(0)e^{rt}

In which P(0) is the initial investment and r is the interest rate, as a decimal.

If Tanisha has ​$1000 to invest at 7​% per annum compounded semiannually​, how long will it be before she has ​$1600​?

We have to find t for which A(t) = 1600 when P = 1000, r = 0.07, n = 2

A(t) = P(1 + \frac{r}{n})^{nt}

1600 = 1000(1 + \frac{0.07}{2})^{2t}

(1.035)^{2t} = \frac{1600}{1000}

(1.035)^{2t} = 1.6

\log{1.035)^{2t}} = \log{1.6}

2t\log{1.035} = \log{1.6}

t = \frac{\log{1.6}}{2\log{1.035}}

t = 6.83

Using continuous interest 6.83 years before she has ​$1600​

If the compounding is​ continuous, how long will it​ be?

We have that P(0) = 1000, r = 0.07

Then

P(t) = P(0)e^{rt}

1600 = 1000e^{0.07t}

e^{0.07t} = 1.6

\ln{e^{0.07t}} = \ln{1.6}

0.07t = \ln{1.6}

t = \frac{\ln{1.6}}{0.07}

t = 6.71

Using continuous compounding, 6.71 years.

7 0
3 years ago
Whats 1/10 of 6,000<br><br><br>​
Katen [24]

Answer:

600

Step-by-step explanation:

(1 / 10) * 6000

That's it!

6 0
3 years ago
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